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777dan777 [17]
3 years ago
6

The student council has decided to have a raffle at the carnival. They came up with a table to show the relationship between the

number of tickets bought and the number of raffle entries. Explain why it could be helpful for the student council to determine an equation to represent this data.
Mathematics
2 answers:
elena-14-01-66 [18.8K]3 years ago
6 0
Write an equation to find the number of each type of ticket they should sell.Let "x" be # of adult tickets; Let "y" be # of student tickets: Value Equation: 5x+3y=450-------------------------- b. Graph your equation.y = (-5/3)x+150
c. Use your graph to find two different combinations of tickets sold.I'll leave that to you.

umka2103 [35]3 years ago
4 0

Looking at a table only gives you a small number of data points, whereas an equation can be used to find any data point.

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I need help with math it’s urgent thanks
Artemon [7]

Answer:

(1, 3)

Step-by-step explanation:

 2x + 3y =  11      ------------(i)

-4x + 2y = 2        ------------(ii)

Multiply equation (i) by 2.

(i)*2              4x + 6y = 22

(ii)               <u>-4x  + 2y = 2</u>                  {Now add and x will be eliminated}

                            8y = 24

y= 24/8

y = 3

Plugin the value of y in equation (i)

2x + 3*3 = 11

2x + 9 = 11

2x = 11-9

2x = 2

x = 2/2

x = 1

8 0
2 years ago
8 - 3x = 17<br> Solve the equation
777dan777 [17]
8-3x=17 substract 8
-8 -8
-3x=17-8
-3x=9 divide by -3
/-3 /-3
x=9/-3
x=-3 Solved for x
4 0
2 years ago
Solve (x – 3)2 = 49. Select the values of x.
PIT_PIT [208]

Answer:

<h3>x = 27.5</h3>

Step-by-step explanation:

(x - 3)2 = 49 \\  \frac{(x - 3)2}{2}  =  \frac{49}{2}  \\ x - 3 = 24.5 \\ x - 3 + 3 = 24.5 + 3 \\ x = 27.5 \\

6 0
2 years ago
Read 2 more answers
Sometimes life is tricky.
skad [1K]

thanks for the message !!

3 0
2 years ago
Read 2 more answers
Let u = (1,2), v = (−3,4), and w = (5,0)
sergij07 [2.7K]

Answer:

w-2u-v

Step-by-step explanation:

Given are three vectors u, v and w.

In R^2 we treat first element as x coordinate and 2nd element as y coordinate.

Thus we mark (1,2) in the I quadrant, (-3,4) in II quadrant and (5,0) on positive x axis 5 units form the origin.

b) w=au+bv

We have to find the values of a and b

(5,0) = a(1,2)+b(-3,4)]

Equate the corresponding terms

5=a-3b\\0=2a+4b

Divide II equation by 2 to get

0=a+2b

Eliminate a

-5 = 5b: b=-1

a=-2

Hence

w = 2u-v

7 0
3 years ago
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