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Olegator [25]
3 years ago
10

A producer plans an outdoor concert for the weekend. The cost of the concert is $8,000 which includes advertising, security, pri

nting, tickets, etc. The producer plans to profit $15,000 if all goes well. However, it it rains, the concert will be canceled. The chance of rain is 0.3 according to the weather report. Find the producer’s expected profit.
Mathematics
1 answer:
andrey2020 [161]3 years ago
3 0

Answer: $8,100

Step-by-step explanation:

If it does not rain, the producer stands to make a profit of $15,000.

If it rains, the producer will lose the $8,000 they invested.

The chance of rain is 0.3 which means the chance it does not rain is 0.7.

Producer's expected profit is the weighted average of these outcomes;

= (15,000 * 0.7) + ( -8,000 * 0.3)

= 10,500 + ( - 2,400)

= $8,100

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From a piece of tin in the shape of a square 6 inches on a side, the largest possible circle is cut out. What is the ratio of th
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Answer:

\sf \dfrac{1}{4} \pi \quad or \quad \dfrac{7}{9}

Step-by-step explanation:

The <u>width</u> of a square is its <u>side length</u>.

The <u>width</u> of a circle is its <u>diameter</u>.

Therefore, the largest possible circle that can be cut out from a square is a circle whose <u>diameter</u> is <u>equal in length</u> to the <u>side length</u> of the square.

<u>Formulas</u>

\sf \textsf{Area of a square}=s^2 \quad \textsf{(where s is the side length)}

\sf \textsf{Area of a circle}=\pi r^2 \quad \textsf{(where r is the radius)}

\sf \textsf{Radius of a circle}=\dfrac{1}{2}d \quad \textsf{(where d is the diameter)}

If the diameter is equal to the side length of the square, then:
\implies \sf r=\dfrac{1}{2}s

Therefore:

\begin{aligned}\implies \sf Area\:of\:circle & = \sf \pi \left(\dfrac{s}{2}\right)^2\\& = \sf \pi \left(\dfrac{s^2}{4}\right)\\& = \sf \dfrac{1}{4}\pi s^2 \end{aligned}

So the ratio of the area of the circle to the original square is:

\begin{aligned}\textsf{area of circle} & :\textsf{area of square}\\\sf \dfrac{1}{4}\pi s^2 & : \sf s^2\\\sf \dfrac{1}{4}\pi & : 1\end{aligned}

Given:

  • side length (s) = 6 in
  • radius (r) = 6 ÷ 2 = 3 in

\implies \sf \textsf{Area of square}=6^2=36\:in^2

\implies \sf \textsf{Area of circle}=\pi \cdot 3^2=28\:in^2\:\:(nearest\:whole\:number)

Ratio of circle to square:

\implies \dfrac{28}{36}=\dfrac{7}{9}

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