Ask question

Ask question

All categories

2 years ago

11

The Lewis family went out to an expensive restaurant for dinner. The bill was $108.00. Mr.Lewis wanted to leave a 15% tip. How m

uch did he pay in all, including the tip?

1 answer:

Luden [163]2 years ago

3 0

So you find 15% of the $108 which is $16.20 you do this by 15/100*108. Then you add $16.20 to 108 and you get $124.20.

So the answer is $124.20

You might be interested in

What is a matrix for a system of equations that does not have a unique solution?

vlada-n [284]

A system of linear equations can have no solution, a unique solution or infinitely many solutions. A system has no solution if the equations are inconsistent, they are contradictory. for example 2x+3y=10, 2x+3y=12 has no solution. is the rref form of the matrix for this system.

This is in my opinion. Im not sure if it is correct or not but Good luck!

4 0

3 years ago

Please help i really need this

lorasvet [3.4K]

Answer:

ok put me brainliest please

its 215$

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

A projectile is launched from ground level with an initial velocity of v0 feet per second. Neglecting air resistance, its height

olya-2409 [2.1K]

Step-by-step explanation:

I've posted solutions in the picture. Rather the ways to solve them. Check and find answers on your own.

Also, I've not solved the problem by differential calculus. You can, obviously, if you're interested. Use it for ease and for tougher equations.

3 0

2 years ago

Sally used 30 cubes to build a rectangular prism that was 5 cubes long. 3 cubes wide, and 2 cubes high. She decided to take apar

cestrela7 [59]

length: 10

width: 3

height: 1

10 x 3 x 1=30

5 0

3 years ago

Read 2 more answers

Limit xtens to 0 x^2logx^2 what is the ans of interminate forms?

GarryVolchara [31]

Rewrite the limit as

$\displaystyle\lim_{x\to0}x^2\log x^2=\lim_{x\to0}\frac{\log x^2}{\frac1{x^2}}$

Then both numerator and denominator approach infinity (with different signs, but that's not important). Applying L'Hopital's rule, we get

$\displaystyle\lim_{x\to0}\frac{\log x^2}{\frac1{x^2}}=\lim_{x\to0}\frac{\frac2x}{-\frac2{x^3}}=\lim_{x\to0}-x^2=\boxed{0}$

7 0

3 years ago