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allsm [11]
3 years ago
10

V-15=-27 what's they equation

Mathematics
2 answers:
Simora [160]3 years ago
8 0
V=-27+15
V= -12

The answer is -12
andrezito [222]3 years ago
7 0
V would be equal to -12
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The term to term rule of another sequence is multiply by 2 and add 3 .
Rashid [163]

Answer:

The first term = 2

Step-by-step explanation:

As the term to term rule of another sequence is:

  • Multiply by 2 and add 3.

So

if

3rd term =  17                        

then

  • 4th term = 17×2 + 3 = 37      
  • 5th term = 37 ×2 + 3 = 77    
  • 6th term = 77 ×2 + 3 = 157    
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following this pattern

3rd term = 7×2  +3 = 17

2nd term = 2 ×2 +3 = 7

1st term = -0.5 ×2 +3 = 2

3 0
4 years ago
Optimization Calculus Problem
frosja888 [35]
\bf \begin{cases}
V_c=\textit{cylinder's volume}\\
V_h=\textit{hemisphere's volume}\\
A_c=\textit{area of the cylinder}\\
A_h=\textit{area of the hemisphere}
\end{cases}
\\\\\\
V_c+V_h=6000\implies (\pi r^2h)+\left( \frac{2\pi r^3}{3} \right)
\\\\\\
6000=\cfrac{3\pi r^2h+2\pi r^3}{3}\implies 18000-2\pi r^3=3\pi r^2h
\\\\\\
\boxed{\cfrac{6000}{\pi r^2}-\cfrac{2r}{3}=h}
\\\\
-------------------------------\\\\



\bf A_c=2\pi rh+2\pi r^2\implies A_c=2\pi r\left(\cfrac{6000}{\pi r^2}-\cfrac{2r}{3}  \right)+2\pi r^2
\\\\\\
A_c=\cfrac{12000}{r}-\cfrac{4\pi r^2}{3}\impliedby \textit{say it has a cost of 1, so stays the same}\\\\
-------------------------------\\\\
A_h=2\pi r^2\impliedby \textit{has a cost of 8 times the cylinder's}
\\\\\\
A_h=16\pi r^2\\\\
-------------------------------\\\\


\bf \textit{total cost is }A_c+A_h
\\\\\\
\cfrac{12000}{r}-\cfrac{4\pi r^2}{3}+16\pi r^2\implies \cfrac{12000}{r}-\cfrac{4\pi r^2}{3}+\cfrac{48\pi r^2}{3}
\\\\\\
\boxed{C(r)=\cfrac{12000}{r}+\cfrac{44\pi r^2}{3}}
7 0
3 years ago
6x-9=0. Which answer shows the equation written in function
fgiga [73]

Answer:

y = 6x - 9

Step-by-step explanation:

The function is; y = 6x - 9

Here, variable x is independent.

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Correct answer will get brainliest!
Natali5045456 [20]
The answer would have to be 5
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Thepotemich [5.8K]

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