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AlladinOne [14]
3 years ago
14

What height on the wall will a 15 foot ladder reach if it is placed 3.5 feet from the base of the wall...???

Mathematics
2 answers:
umka2103 [35]3 years ago
7 0

Answer:

14.6 feet

Step-by-step explanation:

Let the height of the ladder be the hypotenuse, the distance from the wall be the base and the height till the ladder reaches be the perpendicular.

Using Pythogoras theorem,

H^2 = p^2+b^2

p^2 = H^2-b^2

p = under root(H^2-b^2)

p = under root(225 - 12.25)

p = 14.6 feet

Amiraneli [1.4K]3 years ago
7 0
14.6

hope this helps have a blessed day
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A piece of string is 144 inches long. Isabel wants to cut it into 2 pieces so that one piece is five times as long as the other.
Alex Ar [27]

Answer:

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Step-by-step explanation:

The lengths can be found by considering their ratio:

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The sum of the ratio units is 1+5 = 6, and the sum of the lengths is 144 inches. That means each "ratio unit" stands for (144 in)/6 = 24 inches of length.

The lengths are ...

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The pieces are 24 inches and 120 inches in length.

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Equivalently, you can let s represent the shorter length. Then 5s is the longer one, and their total is ...

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5 0
2 years ago
what is the sum of the first five ferms of a geometric series with a1=10 and r=1/5? express your answer as an important fraction
mote1985 [20]
The sum of any geometric sequence, (technically any finite set is a sequence, series are infinite) can be expressed as:

s(n)=a(1-r^n)/(1-r), a=initial term, r=common ratio, n=term number

Here you are given a=10 and r=1/5 so your equation is:

s(n)=10(1-(1/5)^n)/(1-1/5)  let's simplify this a bit:

s(n)=10(1-(1/5)^n)/(4/5)

s(n)=12.5(1-(1/5)^n) so the sum of the first 5 terms is:

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s(5)=12.496

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390500/31240

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3 years ago
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3 years ago
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