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hichkok12 [17]
3 years ago
8

The magnitude of the resultant vector shown is _____.

Mathematics
1 answer:
Flura [38]3 years ago
6 0

Answer:

  2√3

Step-by-step explanation:

You recognize this as a 30°-60°-90° triangle, so you know the hypotenuse (R) is twice the length of the shortest side (√3).

The magnitude of R is 2√3.

_____

In case you haven't memorized the ratios for a 30°-60°-90° triangle, you can use trigonometry and the fact that ...

  Sin = Opposite/Hypotenuse

  sin(30°) = √3/R

  R = √3/sin(30°) = √3/(1/2) = 2√3

Of course, doing this on your calculator will give a numerical answer, which you may not want.

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Airida [17]
3.5 = 7/2 = 3 1/2

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3 years ago
Read 2 more answers
Which equation has no solution? *
Marianna [84]

Answer:

the first one

Step-by-step explanation:

the 4x's cancel out and 8 does not equal -14 so...

8 0
3 years ago
How many pieces of ribbon can you cut from 10 meters, if each piece is 4<br>cm long?​
malfutka [58]

Answer:

answer:250 pieces

1 metre=100cm so

10metres =100*10 =1000cm

each piece is 4 CM long, so.,

no. of pieces=1000/4

by dividing by 2....

=500/4

again by dividing by2...

=250/1=250 pieces

so 250 pieces of ribbon can be cuttted from 10 metre long ribbon.

7 0
3 years ago
Please help me out....
Agata [3.3K]

Answer:

x = 6

Step-by-step explanation:

Given that the line segment is an angle bisector then the following ratios are equal

\frac{42}{78} = \frac{6x-1}{10x+5}, that is

\frac{7}{13} = \frac{6x-1}{10x+5} ( cross- multiply )

13(6x - 1) = 7(10x +5) ← distribute parenthesis on both sides

78x - 13 = 70x + 35 ( subtract 70x from both sides )

8x - 13 = 35 ( add 13 to both sides )

8x = 48 ( divide both sides by 8 )

x = 6

7 0
3 years ago
The 3rd term of (a-b)4 is
fgiga [73]

The third term of the expansion is 6a^2b^2

<h3>How to determine the third term of the expansion?</h3>

The binomial term is given as

(a - b)^4

The r-th term of the expansion is calculated using

r-th term = C(n, r - 1) * x^(n - r + 1) * y^(r - 1)

So, we have

3rd term = C(4, 3 - 1) * (a)^(4 - 3 + 1) * (-b)^(3-1)

Evaluate the sum and the difference

3rd term = C(4, 2) * (a)^2 * (-b)^2

Evaluate the exponents

3rd term = C(4, 2) * a^2b^2

Evaluate the combination expression

3rd term = 6 * a^2b^2

Evaluate the product

3rd term = 6a^2b^2

Hence, the third term of the expansion is 6a^2b^2

Read more about binomial expansion at

brainly.com/question/13602562

#SPJ1

4 0
1 year ago
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