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melisa1 [442]
2 years ago
5

I need help with something in school.

Mathematics
2 answers:
Vanyuwa [196]2 years ago
7 0

Answer:

ask......

Step-by-step explanation:

Kamila [148]2 years ago
6 0

Answer:

what do you need help with

Step-by-step explanation:

:)

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The salary of teachers in a particular school district is normally distributed with a mean of $50,000 and a standard deviation o
andrey2020 [161]

Answer:

D. 54,900

Step-by-step explanation:

We have been given that the salary of teachers in a particular school district is normally distributed with a mean of $50,000 and a standard deviation of $2,500.

To solve our given problem, we need to find the sample score using z-score formula and normal distribution table.

First of all, we will find z-score corresponding to probability 0.975(1-0.025) using normal distribution table.  

From normal distribution table, we get z-score corresponding is 1.96.

Now, we will use z-score formula to find sample score as:

z=\frac{x-\mu}{\sigma}, where,

z = Z-score,

z = Sample score,

\mu = Mean,

\sigma = Standard deviation

1.96=\frac{x-50,000}{2,500}

1.96*2,500=\frac{x-50,000}{2,500}*2,500

4900=x-50,000

4900+50,000=x-50,000+50,000

54900=x

Therefore, the salary of $54900 divides the teachers into one group that gets a raise and one that doesn't.

4 0
3 years ago
THIS IS WORTH 44 POINTS!!
alukav5142 [94]
Hello there! 


Your answer would be 

CAT (top line) = DBU (bottom line)


CAT (bottom line) = BZS (top line)


Hope I helped!

Let me know if you need anything else!

~ Zoe
7 0
3 years ago
Read 2 more answers
Simplify -3(2x-4)+8x-8
ryzh [129]
-3(2x-4)+8x-8
-6x+12+8x-8
2x+4
x=2
3 0
3 years ago
Read 2 more answers
Use Euler's method with step size 0.2 to estimate y(1), where y(x) is the solution of the initial-value problem y' = x2y − 1 2 y
irina [24]

Answer:

Therefore the value of y(1)= 0.9152.

Step-by-step explanation:

According to the Euler's method

y(x+h)≈ y(x) + hy'(x) ....(1)

Given that y(0) =3 and step size (h) = 0.2.

y'(x)= x^2y(x)-\frac12y^2(x)

Putting the value of y'(x) in equation (1)

y(x+h)\approx y(x) +h(x^2y(x)-\frac12y^2(x))

Substituting x =0 and h= 0.2

y(0+0.2)\approx y(0)+0.2[0\times y(0)-\frac12 (y(0))^2]

\Rightarrow y(0.2)\approx 3+0.2[-\frac12 \times3]    [∵ y(0) =3 ]

\Rightarrow y(0.2)\approx 2.7

Substituting x =0.2 and h= 0.2

y(0.2+0.2)\approx y(0.2)+0.2[(0.2)^2\times y(0.2)-\frac12 (y(0.2))^2]

\Rightarrow y(0.4)\approx  2.7+0.2[(0.2)^2\times 2.7- \frac12(2.7)^2]

\Rightarrow y(0.4)\approx 1.9926

Substituting x =0.4 and h= 0.2

y(0.4+0.2)\approx y(0.4)+0.2[(0.4)^2\times y(0.4)-\frac12 (y(0.4))^2]

\Rightarrow y(0.6)\approx  1.9926+0.2[(0.4)^2\times 1.9926- \frac12(1.9926)^2]

\Rightarrow y(0.6)\approx 1.6593

Substituting x =0.6 and h= 0.2

y(0.6+0.2)\approx y(0.6)+0.2[(0.6)^2\times y(0.6)-\frac12 (y(0.6))^2]

\Rightarrow y(0.8)\approx  1.6593+0.2[(0.6)^2\times 1.6593- \frac12(1.6593)^2]

\Rightarrow y(0.6)\approx 0.8800

Substituting x =0.8 and h= 0.2

y(0.8+0.2)\approx y(0.8)+0.2[(0.8)^2\times y(0.8)-\frac12 (y(0.8))^2]

\Rightarrow y(1.0)\approx  0.8800+0.2[(0.8)^2\times 0.8800- \frac12(0.8800)^2]

\Rightarrow y(1.0)\approx 0.9152

Therefore the value of y(1)= 0.9152.

4 0
3 years ago
Laurie buys four bags of candy with 10 pieces of candy in each bag. Her father then gives her 5 more pieces of candy. Laurie wan
Alborosie
Your Question:
<span>Laurie buys four bags of candy with 10 pieces of candy in each bag. Her father then gives her 5 more pieces of candy. Laurie wants to give as much of her candy as she can to each of her six friends, and she wants to make sure they each get an equal number of pieces. How many pieces will be left over, if any, after Laurie gives her friends the candy?
My Answer:
If Laurie has four bags with ten pieces in each bag, and if her father gives her five more pieces,  she would have forty-five pieces and if she has six friends and wants to share it equally with six friends. Each friend would get 7 pieces.
My Work:
<span>45 ÷ 6 = 7.5 
</span>Hope I helped
♥ James.</span>
7 0
3 years ago
Read 2 more answers
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