A. Yes because it passes the vertical line test
Same as any other midpoint of line segment or two points, it is the average of the two points x and y coordinates...
mp=((x1+x2)/2, (y1+y2)/2)
mp=((-6+16)/2, (-9+5)/2)
mp=(10/2, -4/2)
mp=(5, -2)
The function is undefinded if the denominator, x-5, equals 0.
So
.
The domain is
.
In interval notation, this is (-infinity, 5) u (5, infinity).
Answer:
1.A 2.yes
Step-by-step explanation:
PEMDAS
9514 1404 393
Answer:
6.2
Step-by-step explanation:
We presume your "k-value" is the k in the exponential decay term ...
e^(-kt) . . . where t is the number of time units
This is 1/2 when ...
ln(1/2) = -kt
t = ln(1/2)/(-k) = ln(2)/k
t = 0.69315/0.1124 ≈ 6.2
The half life is about 6.2 time units.
