19. If the pg", and "terms of an A.P. are a,b, and c respectively. prove that: p(b-c) + (ca) + rſa-b) = 0 50 Approved by Curricu
lum Development Centre
1 answer:
Answer:
Step-by-step explanation:a = m + (p-1)*d
b = m + (q-1)*d
c = m + (r-1)*d
p(b-c) = p*(q-r)*d
q(c-a) = q*(r-p)*d
r(a-b) = r*(p-q)*d
p(b-c)+q(c-a)+r(a-b)
= p*(q-r)*d + q*(r-p)*d +r*(p-q)*d
= (pq-pr+qr-pq+rp-qr)*d
= 0*d = 0
So i prove p(b-c)+q(c-a)+r(a-b)=0 hope this is helpfull
You might be interested in
Answer:
2 multiplied by a number (m) added to 6
In 11 weeks they will both be 162lbs each
Answer:
You multiply by 6 and the 5th term is 60
Step-by-step explanation:
15*4 = 60
Answer:
a
Step-by-step explanation:
Answer:
a = 4
Step-by-step explanation:
STEP 1) 4a - 16 = 4 • (a - 4)