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Misha Larkins [42]
3 years ago
7

A 10-foot ladder is leaned against a wall. The angle between the base of the ladder and the ground measures 62°. How far up the

wall does the ladder reach from the ground rounded to the nearest tenth?
Mathematics
1 answer:
aalyn [17]3 years ago
6 0
To solve this problem you must apply the proccedure shown below:

 1. You have that:

 - The<span>10-foot ladder is leaned against a wall.
 - The angle between the base of the ladder and the ground measures 62°.

 2. Therefore, you have:

 Sin</span>α=opposite/hypotenuse

 α=62°
 opposite=x
 hypotenuse=10

 3. Therefore, when you clear "x", you obtain:

 Sin(62°)=x/10
 (10)(Sin(62°))=x
 x=8.82

 <span>How far up the wall does the ladder reach from the ground rounded to the nearest tenth?
</span>
 The answer is: 8.82 ft
 

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