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fomenos
3 years ago
13

The area of the conference table in Mr. Nathan’s office must be no more than 175 ft2. If the length of the table is 18 ft more t

han the width, x, which interval can be the possible widths?
Mathematics
1 answer:
stich3 [128]3 years ago
7 0
The answer i think is.       If<span> the </span>length<span> of the </span>table<span> is </span>18 ft more than<span> the </span>width<span>, </span>x, which - 1447102. ... Thearea<span> of the </span>conference table<span> in </span>Mr<span>. </span>Nathan's office must<span> be </span>no more than 175 ft2<span> ... Therefore, the</span>interval<span> 0 < </span>x<span> ≤ 7 represents the possible widths</span>
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A rectangular park measures 300ft by 400ft. A sidewalk runs diagonally from one corner to the opposite corner. Find the lunch of
saveliy_v [14]
When we are given a line cutting diagonally from one corner of a rectangle to the opposite corner, we are given two triangles.

300ft
____
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| / |
| / |
| / |400ft
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-------

*not to scale

Now, using the right-angle trigonometry rule, we can find the hypotenuse (the diagonal line) which represents the footpath.

a^2 + b^2 = c^2

{where a is one side length, b is another side length, and c is the hypotenuse}

Thus, we make c the subject of the equation and substitute the other known values:

c^2 = 400^2 + 300^2
= 160,000 + 90,000
= 250,000

Now we move the 'squared' (^2) from the left hand side to the right hand side. When moving it across the equal sign (=) the result becomes the 'root' of itself:

c = _/250,000
= 500

Therefore, the length of the diagonal path is 500ft.
5 0
3 years ago
Today only, a desk is being sold at a 35% discount. The sale price is $611.
vaieri [72.5K]
The price was $824.85 before the discount (yesterday)
5 0
4 years ago
The maximum value of 12 sin 0-9 sin²0 is: -​
jeka57 [31]

Answer:

4

Step-by-step explanation:

The question is not clear. You have indicated the original function as 12sin(0) - 9sin²(0)

If so, the solution is trivial. At 0, sin(0) is 0 so the solution is 0

However, I will assume you meant the angle to be \theta rather than 0 which makes sense and proceed accordingly

We can find the maximum or minimum of any function by finding the first derivate and setting it equal to 0

The original function is

f(\theta) = 12sin(\theta) - 9 sin^2(\theta)

Taking the first derivative of this with respect to \theta and setting it equal to 0 lets us solve for the maximum (or minimum) value

The first derivative of f(\theta) w.r.t \theta is

                        12\cos\left(\theta\right)-18\cos\left(\theta\right)\sin\left(\theta\right)

And setting this = 0 gives

12\cos\left(\theta\right)-18\cos\left(\theta\right)\sin\left(\theta\right) = 0

Eliminating cos(\theta) on both sides and solving for sin(\theta) gives us

sin(\theta) = \frac{12}{18} = \frac{2}{3}

Plugging this value of sin(\theta) into the original equation gives us

12(\frac{2}{3}) - 9(\frac{4}{9} ) = 8 - 4 = 4

This is the maximum value that the function can acquire. The attached graph shows this as correct

3 0
2 years ago
Find the product. 7/10 X 3/6
tiny-mole [99]
7 . 3
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10. . 6


= 21
--------
60

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4 0
3 years ago
-2x-7≥41 in algaebra for
dexar [7]

Answer:

They are equal. x= -24

Step-by-step explanation:

-2x - 7 ≥ 41

First you isolate the variable

-2x -7 ≥ 41

    +7     +7

-2x≥48

then divide each side by -2

x≥-24

Then go back and plug in

-2(-24)-7=

48-7=41

Therefore

41=41

4 0
3 years ago
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