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andrew-mc [135]
3 years ago
15

Add the number of golden rings from the twelve days of Christmas to the number of French hens. What is the total combined number

of golden rings and French hens?
Mathematics
2 answers:
Svet_ta [14]3 years ago
8 0
5 golden rings
3 French hens
3 + 5 = 8
vazorg [7]3 years ago
4 0
5 GOLDEN RING
3 poules français

8 GOLDEN HENS
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It'll tell me if the answer is wrong so ill mark Brainliest to whoever is right
Vinvika [58]
The answer is C

Hope this helped!!
8 0
2 years ago
I want to take my 5 friends to the movie theater. It costs $8.25 a ticket and I want to buy a pound of gummy bears to share with
Nonamiya [84]

Answer:

Whatever the gummy bears cost minus the amount left

Step-by-step explanation:

50= 8.25(5) + gummy bears

50=41.25 + gummy bears

8.75= gummy bears

7 0
3 years ago
What are the solutions to x2 + 8x + 7 = 0
3241004551 [841]
X^2 + 8x + 7 = 0
x^2 + 7x + x + 7 = 0
x(x + 7) + 1(x + 7) = 0
(x + 7) (x + 1) = 0

x = -7      or       x = -1
6 0
3 years ago
Read 2 more answers
If it’s right I will mark you Brainly!!
Free_Kalibri [48]

Answer:

y=x+20

or

y= 1x + 20

Step-by-step explanation:

The formula for slope is y= mx+ b

m is the slope and b is the y-intercept (where the line touches the y-axis

4 0
2 years ago
Radioactive Waste The rate at which radioactive waste is entering the atmosphere at time t is decreasing and is given by Pe^-kt,
Dmitry_Shevchenko [17]

Answer:

\displaystyle{\int^{\infty}_0 {50e^{-0.04t}}\, dt}=1250

Step-by-step explanation:

Given:

T =\displaystyle{\int^{\infty}_0 {Pe^{-kt}} \, dt}

where,

T = total amount of waste

P = 50, the initial rate

k = 0.04

t = time

T =\displaystyle{\int^{\infty}_0 {50e^{-0.04t}} \, dt}

now we need to solve this integral!

T =\displaystyle{50\int^{\infty}_0 {e^{-0.04t}} \, dt}

T = \left|50\left(\dfrac{e^{-0.04t}}{-0.04}\right)\right|^{\infty}_0

T = \left|-1250e^{-0.04t}\right|^{\infty}_0

T = (-1250e^{-0.04(\infty)})-(-1250e^{-0.04(0)})

when any number has a power of negative infinity it is 0. because: a^-{\infty} = \dfrac{1}{a^{\infty}} = \dfrac{1}{\infty} = 0, like something being divided by a very large number!

T = (-1250(0))-(-1250e^0)

T = 1250

this is the total amount of waste

6 0
2 years ago
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