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Orlov [11]
3 years ago
6

Please help I don’t know how to-

Mathematics
1 answer:
aivan3 [116]3 years ago
3 0

Answer:

y is going back by 3's x is going back one

Step-by-step explanation:

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The average daily temperature for july 1963
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It was 63 degrees fahrenheit.
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- 6 * 1/3=?please type the equation and simplify if possible
rosijanka [135]

We have to simplify this as a product of fractions. Notice that the 6 has a negative sign, therefore, the result will be negative. We have then:

-6\cdot\frac{1}{3}=-\frac{6}{1}\cdot\frac{1}{3}=-\frac{6\cdot1}{1\cdot3}=-\frac{6}{3}=-2

therefore, the simplified result is -2

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1 year ago
QUESTION : WHICH LINES ARE PREPENDICULAR ? HOW DO YOU KNOW ? WILL REPORT THE ONES THAT DONT HELP !!!!​
Minchanka [31]

Answer: Lines R and B are perpendicular

Step-by-step explanation: Slope of R is -1 and the slope of B is 1. Perpendicular lines have opposite slopes

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2 years ago
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Please help me with the below question.
VMariaS [17]

By letting

y = \displaystyle \sum_{n=0}^\infty c_n x^{n+r}

we get derivatives

y' = \displaystyle \sum_{n=0}^\infty (n+r) c_n x^{n+r-1}

y'' = \displaystyle \sum_{n=0}^\infty (n+r) (n+r-1) c_n x^{n+r-2}

a) Substitute these into the differential equation. After a lot of simplification, the equation reduces to

5r(r-1) c_0 x^{r-1} + \displaystyle \sum_{n=1}^\infty \bigg( (n+r+1) c_n + (n + r + 1) (5n + 5r + 1) c_{n+1} \bigg) x^{n+r} = 0

Examine the lowest degree term \left(x^{r-1}\right), which gives rise to the indicial equation,

5r (r - 1) + r = 0 \implies 5r^2 - 4r = r (5r - 4) = 0

with roots at r = 0 and r = 4/5.

b) The recurrence for the coefficients c_k is

(k+r+1) c_k + (k + r + 1) (5k + 5r + 1) c_{k+1} = 0 \implies c_{k+1} = -\dfrac{c_k}{5k+5r+1}

so that with r = 4/5, the coefficients are governed by

c_{k+1} = -\dfrac{c_k}{5k+5} \implies \boxed{g(k) = -\dfrac1{5k+5}}

c) Starting with c_0=1, we find

c_1 = -\dfrac{c_0}5 = -\dfrac15

c_2 = -\dfrac{c_1}{10} = \dfrac1{50}

so that the first three terms of the solution are

\displaystyle \sum_{n=0}^2 c_n x^{n + 4/5} = \boxed{x^{4/5} - \dfrac15 x^{9/5} + \frac1{50} x^{13/5}}

4 0
2 years ago
If f(x) -V7-3, complete the following statement (round your answer
nikklg [1K]

Answer:

- 1.67

Step-by-step explanation:

f(x) = \frac{3}{7+2} - \sqrt{7-3}

    =  \frac{3}{9} - \sqrt{4}

    = \frac{1}{3} - 2

    = - 1 \frac{2}{3}

    = -1.6666666

    = -1.67

5 0
2 years ago
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