The answer to the problem are -3 and -8 because the two equation are being solved for 0
The two given angles are vertical angles and equal each other:
3x + 50 = 6x -10
Now solve for x:
Subtract 3x from both sides:
50 = 3x -10
Add 10 to both sides:
60 = 3x
Divide both sides by 3
X = 20
Answer:

Step-by-step explanation:
The shortest distance d, of a point (a, b, c) from a plane mx + ny + tz = r is given by:
--------------------(i)
From the question,
the point is (5, 0, -6)
the plane is x + y + z = 6
Therefore,
a = 5
b = 0
c = -6
m = 1
n = 1
t = 1
r = 6
Substitute these values into equation (i) as follows;




Therefore, the shortest distance from the point to the plane is 