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IgorLugansk [536]
3 years ago
15

PLS HELP... What value of x satisfies the equation below? 5(x - 3)= 10x + 5

Mathematics
2 answers:
VARVARA [1.3K]3 years ago
6 0

Answer:

x = -4

Step-by-step explanation:

5(x−3) = 10x+5

5x−15 = 10x+5 (Simply both sides of the equation)

−5x−15 = 5 (Subtract 10x from both sides)

−5x = 20 (Add 15 to both sides)

−5x /−5  =  20 /−5  (Divide both sides by -5.)

x = -4

olga55 [171]3 years ago
3 0

Answer:

x = - 4

Step-by-step explanation:

First do distributive property

5x-15=10x+5

then add 15

5x=10x+20

-10x

-5x=20

divide 5

x=-4

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2 years ago
A kitten’s mass at birth was 0.09 kilogram. The kitten gained approximately 0.084 kilogram each week. After how many weeks is th
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A kitten’s mass at birth was 0.09 kilogram. The kitten gained approximately 0.084 kilogram each week. After how many weeks is the kitten’s mass 1.098 kilograms?
5 0
2 years ago
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3 0
3 years ago
Use geometric series to find the fraction of 0.8967898989
Sliva [168]

I'm guessing the repeating part is 89 at the end, so that

x=0.8967\overline89\implies10^4x=8967.\overline{89}

Then

10^4x=8967+\displaystyle89\sum_{i=1}^\infty\frac1{100^i}

10^4x=8967+89\left(\dfrac1{1-\frac1{100}}-1\right)

10^4x=8967+\dfrac{89}{99}

x=\dfrac{8967}{10^4}+\dfrac{89}{99\cdot10^4}

x=\dfrac{443911}{495000}

###

An arguably quicker way without using geometric series:

10^4x=8967.\overline{89}

10^6x=896789.\overline{89}

10^6x-10^4x=887822

x=\dfrac{887822}{10^6-10^4}=\dfrac{443911}{495000}

8 0
3 years ago
Need answer to 4 and 5
algol13

Answer:

Substitute n =1, 2, 3, 4, 5 to get the first five terms.

Step-by-step explanation:

(4). $ g_n  = 2 . 3^{n - 1} $

To find the first term, substitute n = 1.

Therefore, $ g_1 = 2 . 3^{1 - 1} = 2 . 3^{0} = 2 . 1  $ = 2

$g_2 = 2 . 3^{2 - 1} = 2 . 3 $ = 6

$ g_3 =  2 . 3^{3 - 1} = 2 . 3^{2} = 2 . 9 $ = 18

$ g_4 = 2 . 3^{4  - 1} = 2 . 3^{3} = 2 . 27 $ = 54

$ g_5 =  2 . 3^{5 - 1} = 2 . 3^{4} = 2 . 81 $ = 168

Therefore the first five terms of the sequence are: 2, 6, 18, 54, 168.

(5). $ t_n = \frac{2}{3}t_{n - 1} $

$ t_2 = \frac{2}{3} t_{2 - 1} = \frac{2}{3}t_1  = \frac{2}{3}6 $ = 4

$ t_3 = \frac{2}{3} t_2 = \frac{2}{3}. 4 = \frac{8}{3} $

$ t_4 = \frac{2}{3}t_3 = \frac{2}{3}\frac{8}{3} = \frac{16}{9} $

$ t_5 = \frac{2}{3}t_4 = \frac{2}{3}\frac{16}{9} = \frac{32}{27} $

Therefore the first five terms in the sequence are: 6, 4, 8/3, 16/9, 32/27.

8 0
3 years ago
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