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konstantin123 [22]
3 years ago
7

Help me please with 1-8

Mathematics
1 answer:
lora16 [44]3 years ago
8 0
⇄≈≈∫ω∛³⊥°⇅≈⇅⇅⇒×∧∞∫∠Ф∪⊃∩Ф°∞⇅∑∪∴⊂⊂⇆⇆∧↔↔¬∅⊕⊄∅⊥㏑Ф∛↑↑∨⇆°
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Identify the constant of<br> proportionality (k)<br> 8Y = 16x<br> k=
RUDIKE [14]

Answer:

JUST WRITE THIS AS YOUR ANSWER

Step-by-step explanation:

Step 1: Put together the general equation.

Step 2: Solve for the constant of proportionality.

Step 3: Plugging the constant into the equation, solve for the unknown variable.

Let's solve a few problems to see how this works, shall we?

Example 1: Y is directly proportional to x. When x = 5, y = 8. What does y equal when x = 9?

First, we set up our general equation. Because y is directly proportional to x, we have:

y = cx

where c is the constant of proportionality. In other words, when x goes up, y goes up, and when x goes down, y goes down.

The next thing we do is plug our values for x and y into the equation so we can solve for c:

8 = (c)(5)

Solving for c, we get c = 8/5 = 1.6 and we plug this into our equation:

y = 1.6x

Now, we can plug x = 9 into the equation to find out what y equals:

y = (1.6)(9)

y = 14.4

So, our answer is 14.4

Example 2: Y is directly proportional to the square of x. When x = 2, y = 32. What does y equal when x = 5?

This time, our general equation is slightly more complicated because x is squared:

y = cx2

Like before, we solve for our constant:

32 = (c)(22)

32 = (c)(4)

We get c = 8:

y = 8x2

Solving for y when x = 5, we get y = (8)(52) = (8)(25) = 200

Example 3: Y is inversely proportional to x. When x = 2, y = 8. What does y equal when x = 24?

This time, because y is inversely proportional to x, our general equation is different:

xy = c

so when x goes up, y goes down, and vise versa. But, other than that, we solve these kinds of problems the same way as direct proportion problems. Solving for the constant, we get:

(2)(8) = c

So c = 16 and our equation is now:

xy = 16

Solving for y when x = 24 we get y = 16/24 = 2/3

Example 4: Y is inversely proportional to the square root of x. When x = 36, y = 2. What does y equal when x = 64?

As before, we set up our equation:

eq001

Since the square root of 36 is 6, it is easy to solve for c:

(6)(2) = c

We get c = 12 and our equation is now:

eq002

Solving for y when x = 64 we get 8y = 12 or y = 12/8 = 1.5 because the square root of 64 is 8.

6 0
3 years ago
50 points i need to know how to plot these
svetlana [45]

x is time and y is pencils that you have

'starts with 90' so at x=0, plot y=90

'gives away 15 every hour' so for every 1 hour, move 15 down on y

so at x=1, do 90-15=75 pencils

at x=2, do 75-15=60 pencils

etc

until you get to

x=6, do 15-15=0 pencils then stop because you can't give away 15 pencils when you have 0

see attachment for plot

I don't know how your segment tool works so you do it

if it draws a line, you only need 2 points, just do when x=0, y=90 and when x=6, y=0

5 0
3 years ago
A number cube labeled 1 to 6 is rolled 450 times. Which is the best prediction for the number of times that the number cube will
Vedmedyk [2.9K]
Haha, I don't think those answers belong to the question asked :P

The probability of rolling less than 3 is 2/6=1/3

So if you rolled 450 times you should expect to roll less than 3:

450(1/3)=150 times.
3 0
3 years ago
given the graph of the line represented by the equation f(x)=-2x+b,if b is increased 4 units, the graph of the new line would be
jek_recluse [69]
Increasing function value shifts the line up.
answer: 2. up
6 0
3 years ago
Which of the following statements is true about an image after a dilation?
tino4ka555 [31]

Answer:

Not sure what the answer choices are, but choose the choice that says the new image is either stretched or shrunk. In a dilation, the shape/corresponding sides of the pre-image are preserved in the new image, but the size of the new image is altered.

Step-by-step explanation:

hope this helps!

6 0
3 years ago
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