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Goryan [66]
2 years ago
13

Pls help and show workings Due ASAP

Mathematics
1 answer:
tester [92]2 years ago
4 0

Answer: B

Step-by-step explanation:

The equation y+2=\frac{3}{4} x-8 is not yet in slope-intercept form(y=mx+b).  Simply subtract 2 from both sides to turn the equation into slope intercept form as y=\frac{3}{4}x-10.  For a line to be perpendicular to another, it must have an opposite reciprocal slope.  A reciprocal is the fraction reversed, where the numerator is the denominator and vice versa.  Thus, 3/4 would become 4/3.  The opposite reciprocal of 3/4 would be -4/3.

The slope of the line given is 3/4.  Thus, simply plug in the opposite reciprocal of 3/4 for the slope to get: y=-\frac{4}{3} x+b.  Then, because the line passes through -12, 1, plug those values in for x and y, respectively.  

1=-\frac{4}{3}*-12+b

1=16+b

-15=b

Thus, the equation of the line is y=-\frac{4}{3} x-15, or B.

Hope it helps :D

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Answer: The possible cordinates (X,Y) of B can be found with the formula Y = √(8^2 - (X- 5)^2) - 7 where  -3 ≤ X ≤ 13

Step-by-step explanation:

The point A is located at (5, -7)

And we know that we have 8 units of difference between A and B.

The equation of a circle centerd in the point (x0, y0) is:

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So we can draw a circle of 8 units around A, and get:

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So for a given value of X, you can find the value of Y. where you need to remember that (8^2 - (X-5)^2) can not be a negative number, so we must have that:

8^2 ≥ (X - 5)^2

So X can go from -3 (because (-3 - 5)^2 = 8^2)

to X = 13 (because (13 - 5)^2 = 8^2)

So X is in the range {-3, 13}

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