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Rufina [12.5K]
3 years ago
13

Hi, thx for helping​

Mathematics
1 answer:
Sliva [168]3 years ago
7 0

Answer:

C. 8.52624...

Step-by-step explanation:

The reason that C is different is because all of the other decimals are terminating decimals (meaning that they end or stop), while C is a repeating decimal, because it never ends.

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Match the multiplication Expressoins to the exponential expressions ​
Harman [31]

Answer:

Step-by-step explanation:

The pattern is easy to see.

8 0
3 years ago
What is the value of the underlined digits? 588_7, 6.409_7, 8.41_3, _0,184,843
irga5000 [103]
The first on is the tenth place
the second one is  the tenth place
the third one is the tenth place
the last one is the millionth place
 
hope i helped :) i might be wrong though


3 0
3 years ago
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Pls help this is pretty urgent
KIM [24]

Answer:

(a)  0

(b)  f(x) = g(x)

(c)  See below.

Step-by-step explanation:

Given rational function:

f(x)=\dfrac{x^2+2x+1}{x^2-1}

<u>Part (a)</u>

Factor the <u>numerator</u> and <u>denominator</u> of the given rational function:

\begin{aligned} \implies f(x) & = \dfrac{x^2+2x+1}{x^2-1} \\\\& = \dfrac{(x+1)^2}{(x+1)(x-1)}\\\\& = \dfrac{x+1}{x-1}\end{aligned}

Substitute x = -1 to find the limit:

\displaystyle \lim_{x \to -1}f(x)=\dfrac{-1+1}{-1-1}=\dfrac{0}{-2}=0

Therefore:

\displaystyle \lim_{x \to -1}f(x)=0

<u>Part (b)</u>

From part (a), we can see that the simplified function f(x) is the same as the given function g(x).  Therefore, f(x) = g(x).

<u>Part (c)</u>

As x = 1 is approached from the right side of 1, the numerator of the function is positive and approaches 2 whilst the denominator of the function is positive and gets smaller and smaller (approaching zero).  Therefore, the quotient approaches infinity.

\displaystyle \lim_{x \to 1^+} f(x)=\dfrac{\to 2^+}{\to 0^+}=\infty

5 0
1 year ago
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-3n 1 <br> write down all the possibles values of n
mars1129 [50]

Answer:

value is -3n 1 =2 OK please follow me and thanks

6 0
2 years ago
The magnitude and direction of two vectors are shown in the diagram. What is the magnitude of their sum? ​
VLD [36.1K]

Separate the vectors into their <em>x</em>- and <em>y</em>-components. Let <em>u</em> be the vector on the right and <em>v</em> the vector on the left, so that

<em>u</em> = 4 cos(45°) <em>x</em> + 4 sin(45°) <em>y</em>

<em>v</em> = 2 cos(135°) <em>x</em> + 2 sin(135°) <em>y</em>

where <em>x</em> and <em>y</em> denote the unit vectors in the <em>x</em> and <em>y</em> directions.

Then the sum is

<em>u</em> + <em>v</em> = (4 cos(45°) + 2 cos(135°)) <em>x</em> + (4 sin(45°) + 2 sin(135°)) <em>y</em>

and its magnitude is

||<em>u</em> + <em>v</em>|| = √((4 cos(45°) + 2 cos(135°))² + (4 sin(45°) + 2 sin(135°))²)

… = √(16 cos²(45°) + 16 cos(45°) cos(135°) + 4 cos²(135°) + 16 sin²(45°) + 16 sin(45°) sin(135°) + 4 sin²(135°))

… = √(16 (cos²(45°) + sin²(45°)) + 16 (cos(45°) cos(135°) + sin(45°) sin(135°)) + 4 (cos²(135°) + sin²(135°)))

… = √(16 + 16 cos(135° - 45°) + 4)

… = √(20 + 16 cos(90°))

… = √20 = 2√5

5 0
3 years ago
Read 2 more answers
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