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Mandarinka [93]
2 years ago
15

Help with algebra 2 i dont know how to do this

Mathematics
1 answer:
EleoNora [17]2 years ago
4 0

Answer:

I cannot see the question clearly. But I know how to do .

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Help help help help
Rainbow [258]

Answer:

17 - 2= 15

so if you do

15 ÷ 3 = 5

so x= 5

6 0
3 years ago
Read 2 more answers
Y=-x-3
nadya68 [22]

Answer: Heyaa! :)

  • <em>1. y=-x-3 = -1</em>

<em>Slope:  </em>−1

<em>y-intercept: </em>(0,−3)

  • <em>2. y=4x-5 =</em> 4

<em>Slope:</em> 4

<em>y-intercept: </em>(0,−5)

  • <em>3. 2x-y=-2 =</em> 2

<em>Slope:</em> 2

<em>y-intercept:</em> (0,2)

  • <em>4. x+y=4 =</em> 1

Slope: −1

<em>y-intercept:</em> (0,4)

  • <em>5. 3x+4y=-12 = - 3/4</em>

<em>Slope: </em>−3/4

<em>y-intercept: </em>

(0,−3)

Hopefully this helps<em> you!</em>

<em />

- Matthew

4 0
2 years ago
<img src="https://tex.z-dn.net/?f=%20%20%5Cfrac%7B3%7D%7B4%7D%20x%20%2B%20%20%5Cfrac%7B5%7D%7B6%7D%20%20%3D%205x%20-%20%20%5Cfra
jonny [76]

Answer:

nos   agoi o se

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
To two decimal places, find the value of k that will make the function f(x) continuous everywhere. f of x equals the quantity 3x
Fiesta28 [93]

Given function is

f(x)=\left\{\begin{matrix}3x+k & x\leq -4 \\ kx^2-5 & x> -4\end{matrix}\right.

now we need to find the value of k such that function f(x) continuous everywhere.

We know that any function f(x) is continuous at point x=a if left hand limit and right hand limits at the point x=a are equal.

So we just need to find both left and right hand limits then set equal to each other to find the value of k

To find the left hand limit (LHD) we plug x=-4 into 3x+k

so LHD= 3(-4)+k

To find the Right hand limit (RHD) we plug x=-4 into

kx^2-5

so RHD= k(-4)^2-5

Now set both equal

k(-4)^2-5=3(-4)+k

16k-5=-12+k

16k-k=-12+5

15k=-7

k=-\frac{7}{15}

k=-0.47

<u>Hence final answer is -0.47.</u>




7 0
3 years ago
The moon has a surface area of approximately 14,650,000 m^2. Estimate its radius to the nearest mile
Elza [17]

\bf \textit{surface area of a sphere}\\\\ SA=4\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ A=14650000 \end{cases}\implies 14650000=4\pi r^2 \\\\\\ \cfrac{14650000}{4\pi }=r^2\implies \cfrac{3662500}{\pi }=r^2\implies \sqrt{\cfrac{3662500}{\pi }}=r\implies 1079.73\approx r

7 0
3 years ago
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