35x=d
43x=d
(x representing time & d representing distance)
coyote in six hours= 258 miles
rabbit in six hours= 210 miles
*conclusion: a coyote ran 48 more miles than the rabbit
Answer:
l=48, w=20
Step-by-step explanation:
Let the width of the pool be w feet, then the length will be:
![l = 2w + 8](https://tex.z-dn.net/?f=l%20%3D%202w%20%2B%208)
The area of the pool is 960 square feet.
This means that:
![w(2w + 8) = 960](https://tex.z-dn.net/?f=w%282w%20%2B%208%29%20%3D%20960)
Expand and rewrite in standard form to get:
![2 {w}^{2} + 8w - 960 = 0](https://tex.z-dn.net/?f=2%20%7Bw%7D%5E%7B2%7D%20%20%2B%208w%20-%20960%20%3D%200)
![{w}^{2} + 4w - 480 = 0](https://tex.z-dn.net/?f=%20%7Bw%7D%5E%7B2%7D%20%20%2B%204w%20%20-%20480%20%3D%200)
![{w}^{2} + 24w - 20w- 480 = 0](https://tex.z-dn.net/?f=%7Bw%7D%5E%7B2%7D%20%20%2B%2024w%20%20%20-%2020w-%20480%20%3D%200)
![{w}(w+ 24) - 20(w + 24) = 0](https://tex.z-dn.net/?f=%7Bw%7D%28w%2B%2024%29%20-%2020%28w%20%2B%2024%29%20%3D%200)
Factor to get:
![(w+ 24)(w - 20) = 0](https://tex.z-dn.net/?f=%28w%2B%2024%29%28w%20%20-%2020%29%20%3D%200)
![w = - 24 \: or \: w = 20](https://tex.z-dn.net/?f=w%20%3D%20%20-%2024%20%5C%3A%20or%20%5C%3A%20w%20%20%20%3D%20%2020)
We discard the negative value because magnitude is positive.
This means
![l = 2 \times 20 + 8 = 48](https://tex.z-dn.net/?f=l%20%3D%202%20%5Ctimes%2020%20%2B%208%20%3D%2048)
Answer:
The diameter of the floor is 6 yards
Step-by-step explanation:
Here, we are to calculate the diameter of a circular floor that has a circumference of 18.84 yards
Mathematically,
C = π * D
where C is the circumference
Plugging the values of the circumference , we have ;
18.84 = 22/7 * D
7 * 18.84 = 22D
D = (7* 18.84)/22 = 5.99 which is approximately 6 yards
Since you know Z = 2, you can plug it into:
Y = 5 · Z²
Y = 5 · (2)²
Y = 5 · 4
Y = 20
Now that you know Y = 20, you can plug it into:
X = 2 + 5Y
X = 2 + 5(20)
X = 2 + 100
X = 102
Now that you have X, plug it into "2+2X=?"
2 + 2x = ?
2 + 2(102) = ?
2 + 204 = ?
206 = ?
Answer:
No
Step-by-step explanation:
The sequence is not an arithmetic sequence. For a sequence to be arithmetic, the difference between consecutive terms is a constant number which is termed as the common difference.
This means that the difference between the second term and the first term must be equal to the difference between the third term and the second term.
In the sequence above, the first term is 10. The difference between the first and second term is 15. When the first term is subtracted from the second, what we get is 5.
Now, let’s look at the third term and the second term. The difference here is 21 minus 15 which equals 6. Now we can see that the common difference is not constant and thus we conclude that the series is not arithmetic.