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lakkis [162]
2 years ago
11

What are the center and radius of the circle given by x^2 + y^2 - 16x + 8y + 4 = 0?

Mathematics
1 answer:
lukranit [14]2 years ago
3 0

The center of the circle = (8, -4)

The radius of the circle =  \sqrt{76}

<h3>Finding the center and radius of a circle from the equation</h3>

The given equation of the circle is:

x^2+y^2-16x+8y+4=0

The equation can be expressed and simplified as:

x^2-16x+y^2+8y=-4\\\\x^2-16y+8^2+y^2+8y+4^2=-4+8^2+4^2\\\\(x-8)^2+(y+4)^2=-4+64+16\\\\(x-8)^2+(y+4)^2=76

The general equation of a circle is:

(x-a)^2+(y-b)^2=r^2

Comparing the two equations:

The center, (a, b) = (8, -4)

The radius, r = \sqrt{76}

Learn more on the equation of a circle here: brainly.com/question/1506955

#SPJ1

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