Answer:
ASA
ΔFGH ≅ ΔIHG ⇒ answer B
Step-by-step explanation:
* Lets revise the cases of congruence
- SSS ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ
- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and
including angle in the 2nd Δ
- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ
≅ 2 angles and the side whose joining them in the 2nd Δ
- AAS ⇒ 2 angles and one side in the first triangle ≅ 2 angles
and one side in the 2ndΔ
- HL ⇒ hypotenuse leg of the first right angle triangle ≅ hypotenuse
leg of the 2nd right angle Δ
* Lets prove the two triangles FGH and IHG are congruent by on of
the cases above
∵ FG // HI and GH is transversal
∴ m∠FGH = m∠IHG ⇒ alternate angles
- In the two triangles FGH and IHG
∵ m∠FHG = m∠IGH ⇒ given
∵ m∠FGH = m∠IHG ⇒ proved
∵ GH = HG ⇒ common side
∴ ΔFGH ≅ ΔIHG ⇒ ASA
* ASA
ΔFGH ≅ ΔIHG
Answer:
m<1 = 39°
m<3 = 180-90-39= 51°
Step-by-step explanation:
Lines AC and DB are diagonals and always meet at right angles.
Kites have two sets of equivalent adjacent sides and one set up of congruent opposite angles.
Answer:
ΔABC ~ ΔDEC
Step-by-step explanation:
Given : DE║AB
Statements Reasons
1). DE║AB 1). Given
2). ∠CDE ≅ ∠CAB 2). Corresponding angles
[Since DE║AB and AC is the transverse]
3). ∠CED ≅ ∠CBA 3). Corresponding angles
[Since DE║AB and BC is the transverse]
4). ΔABC ~ ΔDEC 4). By AA property of similarity
Hence ΔABC is similar to ΔDEC.
To solve -7y > 161, we divide both sides by -7 and we get y < -23. The inequality sign flipped because we divided both sides by a negative number.
To solve 7y > -161, we divide both sides by 7 and it leads to y > -23. The inequality sign does not flip in this case, because we are not dividing both sides by a negative number.
The similarities is that we end up with -23 on the right side, but the inequality signs are different.