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sineoko [7]
3 years ago
5

Quadrilateral ABCD is a parallelogram if its diagonals bisect each other. Prove that Quadrilateral ABCD is a parallelogram by fi

nding the value of x.
A) x = 2
B) x = 3
C) x =- 9|2
D) x = -3|4

Information that goes with the picture:
AO = 5x + 2
BO = x − 1
CO = 3x − 7
DO = 3x + 8

Mathematics
1 answer:
beks73 [17]3 years ago
5 0

Because this is a parallelogram, we know that the diagonals bisect. This means that AO = DO, and CO = BO

It doesn't matter which two segments we use, but I'm going to use CO = BO for this one.

3x - 7 = x - 1

2x = 6

x = 3

Option B. is the answer.

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Answer:

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While B and D both equal approximately 1.7. B is the simplified form, So B is the answer

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<u>Given</u>:

The exterior angle P is 74°

The measure of ∠PRQ is 51°

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<u>Measure of ∠QPR:</u>

From the figure, it is obvious that P is the intersection of the two lines.

The angle 74° and ∠QPR are vertically opposite angles.

Since, vertically opposite angles are always equal, then the measure of ∠QPR is 74°

Thus, the measure of ∠QPR is 74°

<u>Measure of ∠PQR:</u>

The measure of ∠PQR can be determined using the triangle sum property.

Thus, we have;

\angle PQR+\angle QPR+\angle PRQ=180^{\circ}

Substituting the values, we get;

\angle PQR+74^{\circ}+51^{\circ}=180^{\circ}

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