Answer:
Hello,
I have reply too quick in comments (sorry)
Step-by-step explanation:
For the answer to the question above,
<span>V(n) = a * b^n, where V(n) shows the value of boat after n years.
V(0) = 3500
V(2) = 2000
n = 0
V(0) = a * b^0 = 3500
a = 3500
V(2) = a * b^2
2000 = 3500 * b^2
b = sqrt (2000/3500)
b ≈ 0.76
V(n) = 3500 * 0.76^n
We can check it for n = 1 which is close to 2500 in the graph:
V(1) = 3500 * (0.76)^1
V(1) = 2660
And in the graph we have V(3) ≈ 1500,
V(n) = 3500 * (0.76)^3 ≈ 1536
Now n = 9.5
V(9.5) = 3500 * (0.76)^(9.5)
V(9.5) ≈ 258</span>
Answer:
1.) r>-3/4 and 2.) 157<-1
Answer: Mrs.Buller collects a 500-ml sample of seawater for her chemistry class, and it has 1.94% of chlorine, we have to determine the amount of chlorine in the sample:
Therefore the chlorine content in 500ml of water is 9.7ml.
Y=|x-7| because in order to go to the right you have to subtract the amount from x
