Answer:
Step-by-step explanation:
a(1) = -7 (given)
a(2) = a(1) + 4 = -7 + 4 = -3
a(3) = a(2) + 4 = -3 + 4 = 1
a(4) = a(3) + 4 = 1 + 4 = 5
and so on.
Answer:
2√(17) or about 8.2462 units.
Step-by-step explanation:
We want to determine the distance between the two points (-10, -7) and (-8, 1).
We can use the distance formula. Recall that:

Substitute and evaluate:

Hence, the distance between (-10, -7) and (-8, 1) is 2√(17) units or about 8.2462 units.
Answer:
15a^5b^15
Step-by-step explanation:
you multiply 5 and 3 to get 15, and then when you are multiplying exponents of variables, you actually add them, so a^2 times a^3 is actually a^5, and b^7 times b^8 is b^15. Because these are all multiplied together, you get the answer of 15a^5b^15.
Answer:
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Interesting question. Good to know for computer science.
Suppose you have a function like
an = 3x - 2 Try the first couple
a1 = 3(1) - 2
a1 = 3 - 2
a1 = 1
a2 = 3(2) - 2
a2 = 6 - 2
a2 = 4 So each term differs by 3
a2 - a1 = 3
an = a_(n - 1) + 3
a3 = a2 + 3
a3 = 4 + 3
a3 = 7
a4 = a3 + 3
a4 = 7 + 3
a4 = 10
a5 = a4+ 3
a5 = 10 + 3
a5 = 13
I'll do one more and then check it.
a6 = a5 + 3
a6 = 13 + 3
a6 = 16
a6 = 3x -2
a6 = 3*6 - 2
a6 = 18 - 2
a6 = 16 which checks.
So the general formula is
an = a_(n - 1) * k if you were multiplying or
an = a_(n - 1) + k if you were adding. The key thing is that you are working with the previous term.