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4 years ago

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Kiran read for x minutes, and Andre read for 5/8 more than that. Write an equation that relates the number of minutes Kiran read

with y, the number of minutes that Andre read. Use decimals in your equation.

2 answers:

Liula [17]4 years ago

7 0

Answer: $y = 1.625 x$

Step-by-step explanation:

Here x represents the time taken by Kiran in reading (in minutes) and y represents the time taken by Andrew in reading (in minutes).

According to the question,

Andre read for 5/8 more than kiran.

Thus, The time taken by Andrew(in minutes) = time taken by kiran + 5/8 of time taken by kiran

= $x + \frac{5}{8}\times x$

= $\frac{8}{8} + \frac{5}{8}$

= $\frac{13x}{8}$

= $1.625 x$

Thus, required equation,

$y = 1.625 x$

Eva8 [605]4 years ago

6 0

Answer:

The required equation is $y=0.625+x$

Step-by-step explanation:

Given : Kiran read for x minutes, and Andre read for 5/8 more than that.

To find : Write an equation that relates the number of minutes Kiran read with y, the number of minutes that Andre read ?

Solution :

The number of minutes read by Kiran = 'x' minutes.

The number of minutes read by Andre = 'y' minutes.

Andre read for $\frac{5}{8}$ more than that,

The number of minutes Kiran read to the number of minutes that Andre read is given by,

$y=\frac{5}{8}+x$

$y=0.625+x$

Therefore, The required equation is $y=0.625+x$

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Find the volume of the region between the planes x plus y plus 2 z equals 2 and 4 x plus 4 y plus z equals 8 in the first octant

Alex787 [66]

Find the intercepts for both planes.

Plane 1, <em>x</em> + <em>y</em> + 2<em>z</em> = 2:

$y=z=0\implies x=2\implies (2,0,0)$

$x=z=0\implies y=2\implies(0,2,0)$

$x=y=0\implies 2z=2\implies z=1\implies(0,0,1)$

Plane 2, 4<em>x</em> + 4<em>y</em> + <em>z</em> = 8:

$y=z=0\implies4x=8\implies x=2\implies(2,0,0)$

$x=z=0\implies4y=8\impliesy=2\implies(0,2,0)$

$x=y=0\implies z=8\implies(0,0,8)$

Both planes share the same <em>x</em>- and <em>y</em>-intercepts, but the second plane's <em>z</em>-intercept is higher, so Plane 2 acts as the roof of the bounded region.

Meanwhile, in the (<em>x</em>, <em>y</em>)-plane where <em>z</em> = 0, we see the bounded region projects down to the triangle in the first quadrant with legs <em>x</em> = 0, <em>y</em> = 0, and <em>x</em> + <em>y</em> = 2, or <em>y</em> = 2 - <em>x</em>.

So the volume of the region is

$\displaystyle\int_0^2\int_0^{2-x}\int_{\frac{2-x-y}2}^{8-4x-4y}\mathrm dz\,\mathrm dy\,\mathrm dx=\displaystyle\int_0^2\int_0^{2-x}\left(8-4x-4y-\frac{2-x-y}2\right)\,\mathrm dy\,\mathrm dx$

$=\displaystyle\int_0^2\int_0^{2-x}\left(7-\frac72(x+y)\right)\,\mathrm dy\,\mathrm dx=\int_0^2\left(7(2-x)-\frac72x(2-x)-\frac74(2-x)^2\right)\,\mathrm dx$

$=\displaystyle\int_0^2\left(7-7x+\frac74 x^2\right)\,\mathrm dx=\boxed{\frac{14}3}$

3 0

3 years ago

What value of z will make △DEF ≅ △JKI

Leto [7]

Answer:

z = 11

Explanation:

5y + 13 = 6y

Subtract 5y by both sides.

13 = y

Next,

z + 22 = 3z

Subtract z by both sides.

22 = 2z

Then, divide both sides by 2.

11 = z

Finally plug those answers into the equations.

5(13) + 13 = 78

6(13) = 78

(11) + 22 = 33

3(11) = 33

So △DEF ≅ △JKI because the value of z = 11.

6 0

3 years ago

A recipe needs two and one sixth cups of walnuts and eight and one eighth cups of peanuts. How many cups of nuts are needed for

Rudiy27

Answer: You will have one and two sixth cups of nuts in all or 1 2/6 cups.

Step-by-step explanation: 1.) add the first two fractions. 1/6 + 1/6 = 2/6

2.) add the second fractions. 1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8 = 8/8 = 1

3.) add the whole number and fraction. 2/6 + 1 = 1 2/6.

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denis-greek [22]

Answer:

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Step-by-step explanation:

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Other Method:

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Paraphin [41]

Answer:

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