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charle [14.2K]
3 years ago
12

Is the difference of two polynomials always a polynomial? Explain..

Mathematics
1 answer:
gregori [183]3 years ago
8 0
No, most of the time yes unless the difference contains a negative exponent.

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Please Help Fast!!! 20 points <br> Solve the system of equations: <br> 25−x=−4y<br> 3x−2y=30
gogolik [260]

Answer:

(7, -4.5)

Step-by-step explanation:

25−x=−4y  ---> x=25+4y

3x−2y=30

use x to substitute into the second equation

3 (25+4y)-2y = 30

75+12y-2y=30

75+10y=30

10y=-45

y=-4.5

3x-2(-4.5)=30

3x+9=30

3x=21

x=7

check:

25-7=-4*-4.5

18=18 (yes)

3*7-2*-4.5=30

21+9=30

30=30 (yes)

6 0
3 years ago
How many solutions does 33x+99=33x-99 have
FrozenT [24]

Answer:

No real solutions

Step-by-step explanation:

If you rearrange the equation:

33x - 33x = -99 - 99

0x = -198

Anything divided by zero is undefined/no real solution

3 0
3 years ago
Read 2 more answers
F the price of a pair of shoes is $35.00 before tax, and tax is 20%, what will the final price of the pair of shoes be?
azamat

Answer:

$42

Step-by-step explanation:

35·0.20=7

tax is $7

35+7=42

the final price is $42

5 0
3 years ago
1. If I get a loan of $30,000 and I promise to pay in 10 equal instalments of $3,000 each semester, how much interest in total d
Gekata [30.6K]

Answer:

yes because when you multiply 3000 by 10 that gives you a total of 30000 that you paid off

7 0
3 years ago
Evaluate the integral. 3 2 t3i t t − 2 j t sin(πt)k dt
sveta [45]

∫(t = 2 to 3) t^3 dt

= (1/4)t^4 {for t = 2 to 3}

= 65/4.

----

∫(t = 2 to 3) t √(t - 2) dt

= ∫(u = 0 to 1) (u + 2) √u du, letting u = t - 2

= ∫(u = 0 to 1) (u^(3/2) + 2u^(1/2)) du

= [(2/5) u^(5/2) + (4/3) u^(3/2)] {for u = 0 to 1}

= 26/15.

----

For the k-entry, use integration by parts with

u = t, dv = sin(πt) dt

du = 1 dt, v = (-1/π) cos(πt).


So, ∫(t = 2 to 3) t sin(πt) dt

= (-1/π) t cos(πt) {for t = 2 to 3} - ∫(t = 2 to 3) (-1/π) cos(πt) dt

= (-1/π) (3 * -1 - 2 * 1) + [(1/π^2) sin(πt) {for t = 2 to 3}]

= 5/π + 0

= 5/π.

Therefore,

∫(t = 2 to 3) <t^3, t√(t - 2), t sin(πt)> dt = <65/4, 26/15, 5/π>.

3 0
3 years ago
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