Answer:
t≈8.0927
Step-by-step explanation:
h(t) = -16t^2 + 128t +12
We want to find when h(t) is zero ( or when it hits the ground)
0 = -16t^2 + 128t +12
Completing the square
Subtract 12 from each side
-12 = -16t^2 + 128t
Divide each side by -16
-12/-16 = -16/-16t^2 + 128/-16t
3/4 = t^2 -8t
Take the coefficient of t and divide it by 8
-8/2 = -4
Then square it
(-4) ^2 = 16
Add 16 to each side
16+3/4 = t^2 -8t+16
64/4 + 3/4= (t-4)^2
67/4 = (t-4)^2
Take the square root of each side
±sqrt(67/4) =sqrt( (t-4)^2)
±1/2sqrt(67) = (t-4)
Add 4 to each side
4 ±1/2sqrt(67) = t
The approximate values for t are
t≈-0.092676
t≈8.0927
The first is before the rocket is launched so the only valid answer is the second one
Answer:
1. the y-intercept is 9.5 and it means the starting length of the candle
2. the slope is -1/2 and it means that the candle burns 1/2 an inch every hour
3. it burns an inch every 2 hours, it is 9.5 inches long, so 19 hours it'll take to burn.
2 oranges cost $2 . $9 - $2 = $7
then 12 apply of Lisa and 6 apples of Jeremy
= 18 ÷ 7 = 2.57. $2.57 for 6 apples
2.57 ÷ 6 = 0.43 each apple
Answer:
B) 5 5/8in x 9in is your answer
Step-by-step explanation:
First add the bottom numbers together (9+6+9) which gives you 24. Then multiply both sides by 3/8 (15 x 3/8= 5 <u>5/8</u>) and (24 x 3/8= <u>9</u>) making your answer 5 5/8 x 9
