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3 years ago

7

Considerando quadrados da mesma área, com 4 palitos de fósforo formamos um quadrado, com 7 palitos de fósforo 2 quadrados, com 1

0 palitos de fósforo 3 quadrados. Entao, com 40 palitos formamos quantos quadrados?

1 answer:

Nat2105 [25]3 years ago

5 0

Answer:

no espanol

Step-by-step explanation:

caca everyone is a caca

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Delia is bagging 24 onion bagels and 16 plain bagels for her bakery customers. Each bag will hold only 1 type of bagel. Each bag

Mnenie [13.5K]

<h2>Answer:</h2><h2>8 bagels in each bag, 3 bags of onion, 2 bags of plain</h2>

24 onion bagel

16 normal bagel

We need the GCF (Greatest Common Factor) of 16 and 24 to find the answer.

Factors of 16 = 1, 2, 4, 8, 16

Factors of 24 = 1, 2, 3, 4, 6, 8, 12, 24

What is the GCF? It is 8.

Hence, 8 bagels in each bag.

24/8 = 3 bags of onion bagels

and

16/8 = 2 bags of plain bagels

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1 year ago

Write an equation that is 10 less than 3 times a number y, multiplied by 2 and divided by 4. (10 less than 3 times a number y is

IgorC [24]

Answer: (3y - 10)*2÷4

Step-by-step explanation:

Because 10 less than 3 times a number, y, is done first, it is in parenthesis. The 3 is there to represent the "three times" and the -10 is there to represent the "ten less". The *2 is there to represent the "multiplied by two" and the ÷4 is there to represent the "divided by 4"

Hope it helps, and tyvm <3

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2 years ago

Read 2 more answers

A scale drawing of a square desk is ¼ inch to 1 foot. The actual desk is 50 feet wide. What is the area of the desk in the model

NeX [460]

Answer:

Step-by-step explanation:

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2 years ago

Please help. i dont understand what i have to do and how to get it. thank you

rjkz [21]

Answer:

$\left[\begin{array}{ccc}9\\10\\\end{array}\right]$

Step-by-step explanation:

Evaluate 3a by multiplying each element by 3

3a = 3 $\left[\begin{array}{ccc}2\\4\\\end{array}\right]$ = $\left[\begin{array}{ccc}3(2)\\3(4)\\\end{array}\right]$ = $\left[\begin{array}{ccc}6\\12&\\\end{array}\right]$ , then

3a + b

= $\left[\begin{array}{ccc}6\\12\\\end{array}\right]$ + $\left[\begin{array}{ccc}3\\-2\\\end{array}\right]$ ← sum corresponding elements

= $\left[\begin{array}{ccc}6+3\\12-2\\\end{array}\right]$

= $\left[\begin{array}{ccc}9\\10\\\end{array}\right]$

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2 years ago

Komok [63]

Answer:

A

Step-by-step explanation:

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1 year ago