Question

A store sold 70 hammers and ranchers Hammer sold for $10 each in French so for five dollars each a total of 600.00 what's the collected how many hammers were sold and how many wrenches were sold

Answer 1

Answer:

50 hammers and 20 wrenches.

Step-by-step explanation:

Let x represent number of hammers and y represent number of ranchers.

We have been given that a store sold 70 hammers and ranchers. We can represent this information in an equation as:

$x+y=70...(1)$

We are also told that each hammer sold for $10 and each rancher sold for five dollars resulting a total of 600.00. We can represent this information in an equation as:

$10x+5y=600...(2)$

From equation (1), we will get:

$x=70-y$

Substituting this value in equation (2), we will get:

$700-10y+5y=600$

$700-5y=600$

$700-700-5y=600-700$

$-5y=-100$

$\frac{-5y}{-5}=\frac{-100}{-5}$

$y=20$

Therefore, 20 wrenches were sold.

Now, we will substitute $y=20$ in equation (1) as:

$x+20=70$

$x+20-20=70-20$

$x=50$

Therefore, 50 hammers were sold.