2 years ago

17. Find the measures of the length and width of

Mathematics

1 answer:

777dan777 [17]2 years ago

7 0

Answer:

can you click a full photo of this question.

You might be interested in

Domain: -5 -4 -3.-20. 1. 2. 3. 4. 5)

notsponge [240]

Hdjjddjdjdjdkdidididjskdjdjdidiiddiidididdidididididjdjsksksksksksksksksk

8 0

3 years ago

A.)4x-3y=6<br> B.)4x+3y=6<br> C.) 4x-3y=-6<br> D.)4x+3y=-6

natima [27]

C would be my guess here

4 0

3 years ago

a boat traveled at an average speed of 14.4 km/h for 3.5 hours. how far did the boat travel? use d=rt.

Semenov [28]

Answer is in the attachment below.

8 0

3 years ago

Read 2 more answers

What is 1 1/4 divided by 1 2/5 for kahn academy ?

Neko [114]

Answer:

25/28

Step-by-step explanation:

5/4 x 5/7 = 25/28

3 0

3 years ago

Read 2 more answers

At a carnival, contestants are asked to keep rolling a pair of dice until they roll snake eyes. The number of rolls needed has a

Stells [14]

Answer:

The two numbers of rolls are 25.2 and 46.8.

Step-by-step explanation:

The Chebyshev's theorem states that, if X is a r.v. with mean µ and standard deviation σ, then for any positive number k, we have

$P (|X -\mu| < k\sigma) \geq (1-\frac{1}{k^{2}})$

Here

$(1-\frac{1}{k^{2}})=0.75\\\\\Rightarrow \frac{1}{k^{2}}=0.25\\\\\Rightarrow k=\sqrt{\frac{1}{0.25}}\\\\\Rightarrow k=2$

Then we know that,

$|X - \mu| \geq k\sigma,\\\\ \Rightarrow \mu - k\sigma \leq X \leq \mu + k\sigma$ .

Here it is given that mean (µ) = 36 and standard deviation (σ) = 5.4.

Compute the two values between which at least 75% of the contestants lie as follows:

$P(\mu - k\sigma \leq X \leq \mu + k\sigma)=0.75\\\\P(36 - 2\cdot\ 5.4 \leq X \leq 36 + 2\cdot\ 5.4)=0.75\\\\P(25.2\leq X\leq 46.8)=0.75$

Thus, the two numbers of rolls are 25.2 and 46.8.

8 0

2 years ago