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Marina86 [1]
3 years ago
10

A standard number cube is tossed. find p(even or prime).

Mathematics
2 answers:
BlackZzzverrR [31]3 years ago
5 0
The correct answer is: P(even or prime) = 5/6

Explanation:

First the P(E) = Probability of Even = 3/6 = 1/2 (because 2,4,6 are even numbers)
P(p) = Probability of Prime = 3/6 = 1/2 (because 2,3,5 are the prime numbers)

Now
P(even AND prime) = 1/6 (because 2 is not only an even number but also the prime number)

Hence
P(even or prime) = P(E) + P(p) - P(even AND prime) = 1/2+1/2 -1/6 = 5/6
frozen [14]3 years ago
5 0

Answer:

p(even or prime) =   \frac{5}{6}.

Step-by-step explanation:

Given : A standard number cube is tossed.

To find : find p(even or prime).

Solution : We have given that a cube is tossed.

Total number of number in a cube = 1,2,3,4,5,6

Even number = 2,4,6.

Prime number = 2 , 3, 5.

Probability of even number = \frac{3}{6} =  \frac{1}{2}.

Probability of prime number = \frac{3}{6} =  \frac{1}{2}.

P(A orB) = P(A)+P(B).

Then,

2 is even as well as prime So

p(even or prime) = P(even) +P(prime) - P(2).

p(even or prime) =   \frac{1}{2} +  \frac{1}{2}-\frac{1}{6}

p(even or prime) =  1- \frac{1}{6}.

p(even or prime) =   \frac{5}{6}.

Therefore, p(even or prime) =   \frac{5}{6}.

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