Question

A standard number cube is tossed. find p(even or prime).

Answer 1

The correct answer is: P(even or prime) = 5/6

Explanation:

First the P(E) = Probability of Even = 3/6 = 1/2 (because 2,4,6 are even numbers)
P(p) = Probability of Prime = 3/6 = 1/2 (because 2,3,5 are the prime numbers)

Now
P(even AND prime) = 1/6 (because 2 is not only an even number but also the prime number)

Hence
P(even or prime) = P(E) + P(p) - P(even AND prime) = 1/2+1/2 -1/6 = 5/6

Answer 2

Answer:

p(even or prime) =   $\frac{5}{6}$.

Step-by-step explanation:

Given : A standard number cube is tossed.

To find : find p(even or prime).

Solution : We have given that a cube is tossed.

Total number of number in a cube = 1,2,3,4,5,6

Even number = 2,4,6.

Prime number = 2 , 3, 5.

Probability of even number = $\frac{3}{6}$ =  $\frac{1}{2}$.

Probability of prime number = $\frac{3}{6}$ =  $\frac{1}{2}$.

P(A orB) = P(A)+P(B).

Then,

2 is even as well as prime So

p(even or prime) = P(even) +P(prime) - P(2).

p(even or prime) =   $\frac{1}{2}$ +  $\frac{1}{2}$-$\frac{1}{6}$

p(even or prime) =  1- $\frac{1}{6}$.

p(even or prime) =   $\frac{5}{6}$.

Therefore, p(even or prime) =   $\frac{5}{6}$.