Step-by-step explanation:
The center of a circle with 2 end points of a di diameter is the midpoint of the two endpoints.
The formula needed to find the minpoints is
(x,y) = (x2 + x1)/2, (y2 + y1)/2
x2 = 3
x1 = 3
y2 = 0
y1 = -7
midpoint = (3 + 3)/2, (0 - 7)/2
midp[oint = 3,-3.5
The midpoint is the center of the circle. Observe that the signs get changed when entering the values for (x,y)
So far what you have is (x - 3)^2 + (y + 3.5)^2 = r^2
To determine r^2 you need only take the distance from the center to oneof the endpoints.
r^2 = (3 - 3)^2 + (3.5 - 0)^2
r^2 = 3.5^2
r^2 = 12.25
Answer: (x - 3)^2 + (y + 3.5)^2 = 12.25
Answer:
10
Step-by-step explanation:
5! divided by all the repeats so 3!2! = 10 ways
Answer:
(StartRoot 2 EndRoot, negative 1) and (negative StartRoot 2 EndRoot, negative 1)
Step-by-step explanation:
we have
----> equation A
-----> equation B
solve by substitution
substitute equation B in equation A
solve for x
<em>Find the value of y</em>
For 
----> 
For 
----> 
therefore
The solutions are
(StartRoot 2 EndRoot, negative 1) and (negative StartRoot 2 EndRoot, negative 1)
Answer:
Quadrant 1
Step-by-step explanation:
how I understood this is first understanding how a graph works. Once you understand that you can count 13 horizontal on the "X" Axis, then go 18 up on the "Y" axis. you should get a point in the upper left area and that area is called Quadrant 1. Say if 13 was negative instead of going horizontal east you would go horizontal west. And the point should end up in Quadrant 2. Any more questions feel free to ask me below.
Using the slip and slide method:
2x^2+5x-12
x^2+5x-24
(x+8)(x-3)
(x+8/2)(x-3/2)
(x+4)(2x-3)
Final answer: (2x-3)(x+4)
