Does anyone know what this answer is

Write a phrase that means the same <br> as x/4

blagie [28]

Answer:

Do you have choices?

Step-by-step explanation:

Im not sure off the top of my head

6 0

3 years ago

Part 1: Write the equation of the line that passes through the points (–1, –4) and (2, 5).

jeyben [28]

Y - (-4) = (5 - (-4))/(2 - (-1)) (x - (-1))
y + 4 = (5 + 4)/(2 + 1) (x + 1)
y + 4 = 9/3 (x + 1)
y + 4 = 3(x + 1)
y + 4 = 3x + 3
y = 3x + 3 - 4
y = 3x - 1

5 0

3 years ago

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Alondra says that (12 + 31) × 5 is equivalent to 12 + 31 × 5 because of the associative property.

Tju [1.3M]

Answer:

Step-by-step explanation:

The associative property states that you can add or multiply regardless of how the numbers are grouped.

5 0

3 years ago

Read 2 more answers

What equals 120 to find your answer in Applying GCF and LCM

Alisiya [41]

10x12 is equal to 120

3 0

3 years ago

A survey of 76 commercial airline flights of under 2 hours resulted in a sample average late time for a flight of 2.55 minutes.

nika2105 [10]

Answer:

The best point of estimate for the true mean is:

$\hat \mu = \bar X = 2.55$

$2.55-1.96\frac{12}{\sqrt{76}}=-0.148$

$2.55+1.96\frac{12}{\sqrt{76}}=5.248$

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

Step-by-step explanation:

Information given

$\bar X=2.55$ represent the sample mean for the late time for a flight

$\mu$ population mean

$\sigma=12$ represent the population deviation

n=76 represent the sample size

Confidence interval

The best point of estimate for the true mean is:

$\hat \mu = \bar X = 2.55$

The confidence interval for the true mean is given by:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The Confidence level given is 0.95 or 95%, th significance would be $\alpha=0.05$ and $\alpha/2 =0.025$ . If we look in the normal distribution a quantile that accumulates 0.025 of the area on each tail we got $z_{\alpha/2}=1.96$

Replacing we got:

$2.55-1.96\frac{12}{\sqrt{76}}=-0.148$

$2.55+1.96\frac{12}{\sqrt{76}}=5.248$

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

7 0

3 years ago

Does anyone know what this answer is​

Does anyone know what this answer is