Answer:
Step-by-step explanation:
Let
x ----> the measure of one angle of the triangle
y ---> the measure of the second angle
z ----> the measure of the third angle
we know that
The sum of the measure of the interior angles in any triangle must be equal to 180 degrees
-----> equation A
One angle of a triangle measures 10 degrees more than the second
----> equation B
The measure of the third angle is twice the sum of the first two angles
---> equation C
substitute equation B in equation C
----> equation D
substitute equation D and equation B in equation A
solve for y
Find the value of x
Find the value of z
therefore
2+3+2=7
Red has 3
Yellow has 2
2+3=5
5/7 is the fraction of red or yellow marbles in the bag.
Doubling would not change the answer
I can help, but what are you exactly trying to do here?
<span>Length = 1200, width = 600
First, let's create an equation for the area based upon the length. Since we have a total of 2400 feet of fence and only need to fence three sides of the region, we can define the width based upon the length as:
W = (2400 - L)/2
And area is:
A = LW
Substitute the equation for width, giving:
A = LW
A = L(2400 - L)/2
And expand:
A = (2400L - L^2)/2
A = 1200L - (1/2)L^2
Now the easiest way of solving for the maximum area is to calculate the first derivative of the expression above, and solve for where it's value is 0. But since this is supposedly a high school problem, and the expression we have is a simple quadratic equation, we can solve it without using any calculus. Let's first use the quadratic formula with A=-1/2, B=1200, and C=0 and get the 2 roots which are 0 and 2400. Then we'll pick a point midway between those two which is (0 + 2400)/2 = 1200. And that should be your answer. But let's verify that by using the value (1200+e) and expand the equation to see what happens:
A = 1200L - (1/2)L^2
A = 1200(1200+e) - (1/2)(1200+e)^2
A = 1440000+1200e - (1/2)(1440000 + 2400e + e^2)
A = 1440000+1200e - (720000 + 1200e + (1/2)e^2)
A = 1440000+1200e - 720000 - 1200e - (1/2)e^2
A = 720000 - (1/2)e^2
And notice that the only e terms is -(1/2)e^2. ANY non-zero value of e will cause this term to be non-zero and negative meaning that the total area will be reduced. Therefore the value of 1200 for the length is the best possible length that will get the maximum possible area.</span>
They can play a total of 8 doubles matches at once with 2 people left over
