A base is also known as a alkali, soother, or indicator

How does an increase in concentration affect a chemical reaction? (3 points)

Firlakuza [10]

Answer:

Explanation:

1. Increasing the concentrations of reactants in a chemical reaction would affect a reaction positively by increasing the number of collisions within a particular period which in turn increases the rate of reaction.

2. The molecules gains energy,which enable them to move faster and collide with the right energy for a reaction to take place.

3. The average kinetic motion of molecules in a solution can be measured by measuring the temperature. Temperature is a measure of the average kinetic energy of molecules in a solution.

4 0

3 years ago

Which compound reacts with a base in the bicarbonate buffer system in the human body? Carbon dioxide carbonic acid bicarbonate i

denis23 [38]

Bicarbonate buffer system in blood consists of carbonic acid and bicarbonate ion. H2CO3/HCO3-

When a base enters the body the acid part of the buffer reacts with the base.

Thats the carbonic acid (H2CO3) reacts with the base.

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3 years ago

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What is the volume of 0.80 grams of o2 gas at stp? (5 points) group of answer choices 0.59 liters 0.56 liters 0.50 liters 0.47 l

Vladimir [108]

Answer:

0.56L

Explanation:

This question requires the Ideal Gas Law: $PV=nRT$ where P is the pressure of the gas, V is the volume of the gas, n is the number of moles of the gas, R is the Ideal Gas constant, and T is the Temperature of the gas.

Since all of the answer choices are given in units of Liters, it will be convenient to use a value for R that contains "Liters" in its units: $R=0.0821\frac{L\cdot atm}{mol\cdot K}$

Since the conditions are stated to be STP, we must remember that STP is Standard Temperature Pressure, which means $T=273.15K$ and $P=1atm$

Lastly, we must calculate the number of moles of $O_2(g)$ there are. Given 0.80g of $O_2(g)$ , we will need to convert with the molar mass of $O_2(g)$ . Noting that there are 2 oxygen atoms, we find the atomic mass of O from the periodic table (16g/mol) and multiply by 2: $32g\text{ }O_2=1mol\text{ }O_2$