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AleksandrR [38]
3 years ago
5

How do you calculate the number of photons having a wavelength of 10.0 micrometers required to produce 1.0 kilojoules of energy

Chemistry
1 answer:
shtirl [24]3 years ago
4 0

To calculate this,

We know that energy is 1 photon 
E = hc/wavelenth 
wavelength of 10.0 m 

Solution:
h = 6.626 x 10^-34 Jsec 
C = 2.9979 x 10^8 m/sec 
E = 6.626 10^-34 * 2.9979 10^8 / 10 = 1.9864 10^-26J 

Then, the number of photons is computed by:

n = 1000 / 1.9864 10^-26 = 5.04 10^28 photons 

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Is the following chemical equation balanced?
FrozenT [24]

Answer:

No

Explanation:

The given equation is not balanced

Chemical equation:

KClO₄ → KCl + O₂

Given Balanced chemical equation:

KClO₄ → 2KCl + 2O₂

Correctly balanced chemical equation:

2KClO₄ → 2KCl + 4O₂

Now this equation is correctly balanced.

There are two potassium atom two chlorine atoms and eight oxygen atoms on both side of equation. So this is correctly balanced.

Coefficient with reactant and product:

KClO₄    2

KCl        2

O₂         4

5 0
4 years ago
Which describes the composition of carbohydrates?
UkoKoshka [18]

Answer: Carbohydrates (carbo- = “carbon”; hydrate = “water”) contain the elements carbon, hydrogen, and oxygen, and only those elements with a few exceptions. The ratio of carbon to hydrogen to oxygen in carbohydrate molecules is 1:2:1.

HOPE THIS HELPS

CAN U GIVE ME BRAINLIEST

3 0
3 years ago
(Not drawn to scale) 32 What does this model represent? (1) a single atom (3) a mixture (2) a cell (4) a compound Open notes nav
Mademuasel [1]

UwU have a good day bye!

3 0
3 years ago
What is the name given to the tiny clump of positive material at an atom’s center
Mariana [72]
The answer will be the Bohr model
7 0
3 years ago
Find the pH during the titration of 20.00 mL of 0.1000 M butanoic acid, CH3CH2CH2COOH (Ka = 1.54 x 10^-5), with 0.1000 M NaOH so
Vanyuwa [196]

Answer:

pH after the addition of 10 ml NaOH = 4.81

pH after the addition of 20.1 ml NaOH = 8.76

pH after the addition of 25 ml NaOH = 8.78

Explanation:

(1)

Moles of butanoic acid initially present = 0.1 x 20 = 2 m moles  = 2 x 10⁻³ moles,

Moles of NaOH added = 10 x 0.1 = 1 x 10⁻³ moles

                          CH₃CH₂CH₂COOH + NaOH ⇄ CH₃CH₂CH₂COONa + H₂O

Initial conc.            2 x 10⁻³                 1 x 10⁻³           0            

Equilibrium             1 x 10⁻³                   0                  1 x 10⁻³

Final volume = 20 + 10 = 30 ml = 0.03 lit

So final concentration of Acid = \frac{0.001}{0.03} = 0.03mol/lit

Final concentration of conjugate base [CH₃CH₂CH₂COONa]=\frac{0.001}{0.03} = 0.03 mol/lit

Since a buffer solution is formed which contains the weak butanoic acid and conjugate base of that acid .

Using Henderson Hasselbalch equation to find the pH

pH=pK_{a}+log\frac{[conjugate base]}{[acid]}  \\\\=-log(1.54X10^{-5} )+log\frac{0.03}{0.03} \\\\=4.81

5 0
4 years ago
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