The element of the group 17 that is most active non metal is fluorine.
The group 17 of the periodic table contains bromine(Br), iodine(I), Chlorine(Cl) and fluorine(F).
Among all the elements of the group 17. Fluorine is the smallest in size.
Because of the small size of fluorine it has the highest electronegativity in group 17.
This high electronegativity makes it a very active non metal. It provides a very high oxidizing power and low dissociation energy to the fluorine atom.
Also because of the very small size the source of attraction between the nucleus and the electrons is very high in floor in atom.
It reacts readily to form oxides and hydroxides.
So, we can conclude here that fluorine is the most active non metal of group 17.
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Answer:
0.08 mol L-1
Explanation:
Sulfuric acid Formula: H2SO4
Ammonia Formula: NH3
Ammonium sulfate Formula: (NH₄)₂SO₄
H2SO4 + 2NH3 = 2NH4+ + SO4 2-
H2SO4 + 2NH3 = (NH₄)₂SO₄
H2SO4 = (1/2)x (32.8 x 10^-3 L x 0.116 mol L-1)/25 x 10^-3 L
= 0.08 mol L-1
