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ANEK [815]
3 years ago
13

In RST, which is a possible

Mathematics
2 answers:
dimaraw [331]3 years ago
8 0
The possible side length is 7
givi [52]3 years ago
4 0

Answer:

C and D

Step-by-step explanation:

If the angle is greater, it's opposite length is greater

Since angle R is greater than angle T,

ST > SR

So ST > 8

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It’s the same distance from the second base to the first base from the second base to third-base the angle formed by the first b
Margaret [11]

Answer:

Distance of home plate to 1st base is equal to home plate to 3rd base

Step-by-step explanation:

Let's first assign each position:

A: home base

B: 1st base

C: 2nd base

D: 3rd base

The information given:

'It’s the same distance from the second base to the first base from the second base to third-base' tells us BC = CD

'the angle formed by the first base second base and Homeplate has the same measure as the angle formed by the base second base home plate' tells us angle(BCA) = angle(DCA)

Check for congruency between triangle ABC and ADC

BC = CD - side congruency (S)

angle(BCA) = angle(DCA) - angle congruency (A)

CA = CA - side congruency (S)

So triangle ABC and ADC fullfill the criteria of congruence property as SAS.

Since both triangle are congruent, another side of the triangles AB and AD must be the same too.

AB = home plate to 1st base

AD = home plate to 3rd base

Therefore we can conclude that the distance of home plate to 1st base is equal to home plate to 3rd base

3 0
3 years ago
Help plsssssssss ....
erik [133]

Tan is the right answer

hope it helps you ❣❣

<h2>Mark me as brainliest </h2>
4 0
2 years ago
Read 2 more answers
I need a answer A.S.A.P PLEASE WILL GIVE 19 POINTS
Ipatiy [6.2K]

Answer:

Okie when you do these you got to give all information

Step-by-step explanation: because people can help you instead of looking at a picture wonderin what they are they are supposed to do

3 0
3 years ago
Original: $458<br> Discount:<br> New: $137.40
Vanyuwa [196]

Answer:

Your answer would be 30% discount

Step-by-step explanation:

137.40 / 458 = .3

8 0
3 years ago
Find all points on the portion of the plane x+y+z=5 in the first octant at which f(x, y, z) = xy2z2 has a maximum value.
irina1246 [14]
Lagrange multipliers:

L(x,y,z,\lambda)=xy^2z^2+\lambda(x+y+z-5)

L_x=y^2z^2+\lambda=0
L_y=2xyz^2+\lambda=0
L_z=2xy^2z+\lambda=0
L_\lambda=x+y+z-5=0

\lambda=-y^2z^2=-2xyz^2=-2xy^2z

-y^2z^2=-2xyz^2\implies y=2x (if y,z\neq0)

-y^2z^2=-2xy^2z\implies z=2x (if y,z\neq0)

-2xyz^2=-2xy^2z\implies z=y (if x,y,z\neq0)

In the first octant, we assume x,y,z>0, so we can ignore the caveats above. Now,

x+y+z=5\iff x+2x+2x=5x=5\implies x=1\implies y=z=2

so that the only critical point in the region of interest is (1, 2, 2), for which we get a maximum value of f(1,2,2)=16.

We also need to check the boundary of the region, i.e. the intersection of x+y+z=5 with the three coordinate axes. But in each case, we would end up setting at least one of the variables to 0, which would force f(x,y,z)=0, so the point we found is the only extremum.
4 0
3 years ago
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