You know that t=0 and x=0, the car starts moving with a constant acceleration of 2.70m/s²
At the same time, a truck moving speed o 8.50 m/s passes the car
D=v.t (for the truck)
And d= v.t+1/2.a.t²(for the car)
v.t=1/2.a.t²
t=2.v/a
t=2.8.50 m/s/ 2.70 m/s²
17m/2.70=6.29
This mean that the distance is
D=v.t=8.50m/s.6.29= 53.465 m/s
The speed of the car is
Vcar=a.t
2.7m/s2×× 53.65
=144.34
Answer:
He purchased 1.8 pounds.
Step-by-step explanation:
Divide 8.10 by 4.50.
8.10÷4.50= 1.8 pounds.
Hope this helped.
Step-by-step explanation:
1.8×10 to the power of 8
8.0×10 to the power of 6
1.2 ×10 to the power of 6
2.4×10 to the power of 2
Answer:
f(0)
= e^o/2
= 1/2
=0.5 it is the required answer
