All categories

4 years ago

What are the first five multiples of 32

2 answers:

5 0

The first 5 multiples of 32 are

32, 64, 96, 218, 160.

A multiple is merely the number which '32' can turn into if multiplied.
Similarly this can be confused with 'factors' which are the opposite; numbers which go into a certain number.

kykrilka [37]4 years ago

3 0

That all depends on where you start and what direction you go.

If you start at zero and go in the positive direction, then
the first 5 multiples of 32 that you encounter are

32 x 1
32 x 2
32 x 3
32 x 4
32 x 5 .

You can easily simplify those numbers with your calculator.

You might be interested in

A school club wants to buy shirts for each of its 38 members. Each shirt cost $23. About how much money will all the shirts cost

lana66690 [7]

Answer: $874

Step-by-step explanation: multiply 23 by 38 to get the total cost

5 0

3 years ago

Read 2 more answers

Solve each system of equations by graphing 4x-y=5 and. 2x+y=7

vivado [14]

4x-y=5 Would be the y-intercept (0,7) 2x+y=7 Would be the x-intercept (3.5,0)
Sorry if wrong

4 0

4 years ago

a candy necklace is extended from the top of a 10-foot ice cream cone to the ground. The necklace makes a 55 degree angle of the

Finger [1]

Answer:

The length of the necklace is 12.20 foot

Step-by-step explanation:

Given as :

The height of the ice cream cone to the ground = h = 10 foot

The angle make by the necklace of the ice cream cone = 55°

Let The length of the necklace = L foot

<u>Now, from figure </u>

Height = BC = h foot

The length of the necklace = L = AC

So, Sin angle = $\dfrac{\textrm perpendicular}{\textrm hypotenuse}$

Or, Sin 55° = $\dfrac{\textrm BC}{\textrm AC}$

Or, 0.8191 = $\dfrac{h}{L}$

Or, 0.8191 = $\dfrac{10 foot}{L}$

Or, L = $\dfrac{10 foot}{0.8191}$

∴ L = 12.20 foot

So, The length of necklace = L = 12.20 foot

Hence The length of the necklace is 12.20 foot Answer

5 0

3 years ago

Find the Value of Sin A rounded to the nearest hundredth, if necessary.

leonid [27]

Step-by-step explanation:

In trigonometry, the law of sines is an equation that relates the length of the sides of a triangle (any type of triangle) to the sines of its angles. This is expressed mathematically as

$\displaystyle\frac{a}{\sin \alpha} \ = \ \displaystyle\frac{b}{\sin \beta} \ = \ \displaystyle\frac{c}{\sin \gamma}$ ,

where $a$ , $b$ , and $c$ are the lengths of the sides of the triangle and $\alpha$ , $\beta$ , and $\gamma$ are the opposite angles (as shown in the figure below). Likewise, the law is sometimes written as it reciprocals,

$\displaystyle\frac{\sin \alpha}{a} \ = \ \displaystyle\frac{\sin \beta}{b} \ = \ \displaystyle\frac{\sin \gamma}{c}$ .

Therefore,

$\displaystyle\frac{\sin A}{BC} \ = \ \displaystyle\frac{\sin B}{AC} \\ \\ \\ \sin A \ = \ \displaystyle\frac{\sin B \ \times \ BC}{AC} \\ \\ \\\sin A \ = \ \displaystyle\frac{\sin \left(90^{\circ}\right) \ \times \ \sqrt{\left(10\right)^{2} \ - \ \left(\sqrt{78}\right)^{2}}}{10} \\ \\ \\ \sin A \ = \ \dsiplaystyle\frac{\sqrt{22}}{10} \\ \\ \\ \sin A \ = \ 0.47 \ \ \ \ (\text{nearest hundredth})$

Alternatively, you can solve this question using the definition of the trigonometric function sine. For the angle $\theta$ in the figure below,

$\sin \theta \ = \ \displaystyle\frac{\text{opposite}}{\text{hypothenuse}}$ .

Therefore,

$\sin A \ = \ \displaystyle\frac{BC}{AC} \\ \\ \\ \sin A \ = \ \displaystyle\frac{\sqrt{\left(10\right)^{2} \ - \ \left(\sqrt{78}\right)^{2}}}{10} \\ \\ \\ \sin A \ = \ \displaystyle\frac{\sqrt{22}}{10} \\ \\ \\ \sin A \ = \ 0.47 \ \ \ \ (\text{nearest hundredth})$

8 0

3 years ago

If sin(2x) = cos(x + 30°), what is the value of x?

valkas [14]

Answer:

x = -10 ° + π/6 + (2 π n_1)/3 for n_1 element Z

or x = 30 ° + π/2 + 2 π n_2 for n_2 element Z

Step-by-step explanation:

Solve for x:

sin(2 x) = cos(x + 30 °)

Rewrite the right hand side using cos(θ) = sin(θ + π/2):

sin(2 x) = sin(30 ° + π/2 + x)

Take the inverse sine of both sides:

2 x = -30 ° + π/2 - x + 2 π n_1 for n_1 element Z

or 2 x = 30 ° + π/2 + x + 2 π n_2 for n_2 element Z

Add x to both sides:

3 x = -30 ° + π/2 + 2 π n_1 for n_1 element Z

or 2 x = 30 ° + π/2 + x + 2 π n_2 for n_2 element Z

Divide both sides by 3:

x = -10 ° + π/6 + (2 π n_1)/3 for n_1 element Z

or 2 x = 30 ° + π/2 + x + 2 π n_2 for n_2 element Z

Subtract x from both sides:

Answer: x = -10 ° + π/6 + (2 π n_1)/3 for n_1 element Z

or x = 30 ° + π/2 + 2 π n_2 for n_2 element Z

6 0

3 years ago