Answer:
The total displacement of the car is 250 km.
Explanation:
Given that,
A car at a position 150 km [W] of Toronto travels to a position 400 km [W] of Toronto.
Total displacement = final position - initial position
= 400 km - 150 km
= 250 km
So, the total displacement of the car is 250 km.
If a person returns to the position he started again. like moving in a circle track
<span>The correct condition in the nucleus are likely to result in an atom undergoing radioactive decay is that </span><span>d. When the attraction of the strong force is greater than the attraction of the electrostatic force. Radioactivity </span><span>is the process when the unstable nucleus loses energy and emits radiation such as the alpha and beta particles.</span>
Explanation:
We use Hooke's Law, which states that,
F=kx
F- is the force in newtons
k- is the spring constant
x- is the extension of the spring in meters
Solving for k we get k=F/x
k= 10N/0.50m
=100 N/m
The distance covered in one orbit is equal to the circumference of earth.
Given that radius of earth is 3959 miles.
Circumference of earth= 2πr = 2*3.14*3959 = 24875.13 miles
Speed is 26,000 miles per hour.
Since, Velocity= Distance/Time
Time= Distance/Velocity = 24875.13/26000
Time = 0.9567 hours
Therefore,
Average hour per orbit is 0.957 approximately.