Question

A car travels at a constant speed around a circular trackwhose

Answer 1

Answer:

a = 0.77 m/s^2

Explanation:

The centripetal acceleration is given as

$a = \frac{v^2}{R}$

The velocity of the car can be calculated using the circumference of the track and the period of the car.

$2\pi R = v T\\2\pi 2.6 = v 360\\v = 0.045 ~km/s = 45~m/s$

So, the acceleration is

$a = \frac{45^2}{2.6\times 10^3} = 0.77~m/s^2$