Answer: 6/8 + 12/8 + 12/8 + 10/8 = 5
Step-by-step explanation: The answer is five.
Hello,
r=5(1+cos t)
r'=5(-sin t)
r²+r'²= 25[(1+cos t)²+(-sin t)²]=50(1-cos t)=50 sin² (t/2)
Between 0 and π, sin x>0 ==>|sin x|=sin x
![l= 2*5* \int\limits^{\pi}_0{sin( \frac{t}{2} )} \, dt= 5[-cos (t/2)]_0^{\pi}\\\\ =5(0+1)=5](https://tex.z-dn.net/?f=l%3D%202%2A5%2A%20%5Cint%5Climits%5E%7B%5Cpi%7D_0%7Bsin%28%20%5Cfrac%7Bt%7D%7B2%7D%20%29%7D%20%5C%2C%20dt%3D%205%5B-cos%20%28t%2F2%29%5D_0%5E%7B%5Cpi%7D%5C%5C%5C%5C%0A%3D5%280%2B1%29%3D5)
Here is the method but i may have make some mistakes.
<u>Answer</u>:- No.
<u>Explanation</u> :-
<u>Substitute these numbers in pythagoras theorem to check if the set of numbers is a pythagorean triplet.</u>
<u>Pythagoras theorem</u> :- sq. of hypotenuse (longest side) is equal to the sum of sq.s of other two sides.
<u>Here</u>,
hypotenuse = 12 (as it is the longest side)
and other two sides are 6 and 9.
----> 6^2 + 9^2 = 12^2
----> 36 + 81 = 144
----> 117 = 144
Since, LHS is not equal to RHS, this set of numbers is not a pythagorean triplet.
Answer:
157
Step-by-step explanation: