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Masteriza [31]
4 years ago
9

How do I solve 1/3k-2k+4=10

Mathematics
1 answer:
serg [7]4 years ago
4 0
<h3>The value of k is -3.6</h3>

<em><u>Solution:</u></em>

Given that, we have to solve

\frac{1}{3}k -2k + 4 = 10

We have to find solution to given equation

From given,

\frac{1}{3}k -2k + 4 = 10

Make the denominators same in right side of equation

\frac{1}{3}k - \frac{2k \times 3}{1 \times 3} + \frac{4 \times 3}{1 \times 3} = 10\\\\Simplify\\\\\frac{1}{3}k - \frac{6k}{3} + \frac{12}{3} = 10\\\\\frac{k-6k + 12}{3} = 10\\\\Isolate\ for\ k\\\\k - 6k + 12 = 10 \times 3\\\\Combine\ the\ like\ terms\\\\-5k + 12 = 30\\\\-5k = 30 - 12\\\\-5k = 18\\\\Divide\ both\ sides\ by\ -5\\\\k = -3.6

Thus the value of k is -3.6

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See Discussion below

Discussion:

A function f is even if f(-x) = f(x)


f(x)                               f(-x)                                  Are they equal?

----------------------------------------------------------------------------------------

-x^8 + 2x^6-5x           -(-x)^8 + 2(-x)^6 + 5x         No

3 abs(x) - 4                 3 abs(-x) -4                       Yes

log5 x^2                     log5 (-x)^2                        Yes

(6x)^ (1/7)                     (-6x)^(1/7)                          No

e^(x^2-x)                     e^( (-x)^2+x)                      No

(x^8 +5x^2)^(-1)           ( (-x)^8 + 5 (-x)^2) ^(-1)      Yes


Answers with Yes, above are even functions.

Regards,  

MrB

P.S.  I'll be on vacation from Friday, Dec 22 to Jan 2, 2019. Have a Great New Year!


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