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Katen [24]
3 years ago
13

THANKS ONLY PUT AN ANSWER IF YOU KNOW IT

Mathematics
1 answer:
lara [203]3 years ago
7 0
The answer is 3
Hope it helped
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What is 2(5x+3)-6x=7x+30+5x<br> Please show work
earnstyle [38]

Answer: X=-3


Step-by-step explanation:

2(5x+3)-6x=7x+30+5x

10x+6-6x=7x+30+5x

4x-12x=30-6

-8x=24

-x=3

x=-3

5 0
3 years ago
For the linear equation 3x + 4y =6​
vovangra [49]
Answer: 3x+4y-6=0 I don’t know it I’m right but answer should be 0
6 0
3 years ago
Need help on this question​
amm1812

Answer:

3.5 and 3½

Step-by-step explanation:

Half of 7 is positive 3.5 aka 3½. It can't be -7/2 or -3.5 because they result in a negative number. It also can't be 7.2 because that's too big of a number.

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2 years ago
Some Geometry problems I need some help with!
drek231 [11]

Answer:                                                                                

When a 2-D circle is rotated around a line that it does not touch. What is the name of the resulting figure?  

The answer is annulus

A sphere with radius 16 m is cut by a plane though it’s a great circle. What is the best description of the cross section that is shown?

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8 0
4 years ago
Suppose the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.7
Zinaida [17]

Answer:

(a) The probability that the sample average sediment density is at most 3.00 is 0.092.

    The probability that the sample average sediment density is between 2.70 and 3.00 is 0.477.

(b) The sample size must be at least 77.

Step-by-step explanation:

The random variable <em>X</em> ca be defined as the sediment density (g/cm) of a specimen from a certain region.

The random variable <em>X</em> is normally distributed with mean, <em>μ</em> = 2.7 and standard deviation, <em>σ</em> = 0.75.

(a)

A random sample of <em>n</em> = 25 specimens is selected.

Compute the probability that the sample average sediment density is at most 3.00 as follows:

Apply continuity correction:

P(\bar X\leq 3.00)=P(\bar X

                    =P(\bar X

                    =P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}

                    =P(Z

Thus, the probability that the sample average sediment density is at most 3.00 is 0.092.

Compute the probability that the sample average sediment density is between 2.70 and 3.00 as follows:

P(2.70

                                =P(0

*Use a <em>z</em>-table.

Thus, the probability that the sample average sediment density is between 2.70 and 3.00 is 0.477.

(b)

It is provided that:

P(\bar X\leq 3.00)\geq 0.99

P(\bar X

P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}

P(Z

The value of <em>z</em> for the probability above is

<em>z</em> ≥ 2.33

Compute the value of <em>n</em> as follows:

\frac{|2.50-2.70|}{0.75/\sqrt{n}}\geq 2.33

\frac{|-0.20|}{2.33}\geq \frac{0.75}{\sqrt{n}}

\sqrt{n}\geq \frac{0.75\times 2.33}{|-0.20|}\\\sqrt{n}\geq 8.7375\\n\geq 76.3439\\\approx n\geq 77

Thus, the sample size must be at least 77.

8 0
3 years ago
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