The total ball in the bag is 4 + 2 = 6 balls. Their are 4 red balls and 2 blue balls.
If they are drawn singly the probability that 2 blue balls are counted can be expressed as follows
0.63 does not simplify at all, so it stays 63/100. :)
Answer:
-2
Step-by-step explanation:
2(8) - 3(6)
16 -18 = -2
Prob( red die shows > 3) = 1/2
Prob ( green dye shows < 3) = 1/3
Required probability = P( red> 3) * P(green not < 3) + P(red not > 3) * P(green <3)
= 1/3*2/3 + 1/2*1/3
= 7/18
Note i have excluded the possibillty that red > 3 AND green < 3.
Answer:
Where is the question?
Step-by-step explanation: