How do you Evaluate?

1 answer:

3 0

How do you evaluate: To evaluate an algebraic expression, you have to substitute a number for each variable and perform the arithmetic operations. In the example above, the variable x is equal to 6 since 6 + 6 = 12. If we know the value of our variables, we can replace the variables with their values and then evaluate the expression.

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A student answered 140 questions correctly out of 200. What percent is this?

charle [14.2K]

It’s 70%. 140/200=.7 and .7 to percentage is 70%

6 0

3 years ago

You wish to estimate a population proportion with a confidence interval with a margin of error no larger than 0.03. You have a b

NikAS [45]

Answer:

The answer is 0.8788

Step-by-step explanation:

From question given, let us recall the following:

We know that Ƶα /2 * √p (1-p)/n

when we use n≤ 5000/10 =500

P = 0.75

The Margin of error = 0.03

Putting this values together we arrive at

Ƶα/2 = 0.03/√0.75 * 0.25/500

= 1.549

Now,

Ф (1.549) = 0.9394

Therefore the confidence level becomes:

1- (1-∝)/2 = 0.9394

∝ = 0.8788

The answer is 0.8788

8 0

3 years ago

You bought a large cooler that holds 5 gallons. How many quarts is that?

gizmo_the_mogwai [7]

If you buy a 5 gallon cooler, it should be able to hold 20 quarts!!

i hope this helped

7 0

3 years ago

Read 2 more answers

A 500-page book contains 250 sheets of paper. The thickness of the paper used to manufacture the book has mean 0.08 mm and stand

LenaWriter [7]

Answer:

10.20% probability that a randomly chosen book is more than 20.2 mm thick

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

250 sheets, each sheet has mean 0.08 mm and standard deviation 0.01 mm.

So for the book.

$\mu = 250*0.08 = 20, \sigma = \sqrt{250}*0.01 = 0.158$