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3 years ago

i’m having some trouble with these three questions it would be a big help if someone could help me out :)

Mathematics

1 answer:

algol [13]3 years ago

6 0

I’m not sure if I’m right but I think u have to add the 3 largest numbers in the population section and then add the other 3 least numbers in the same section and then u have to subtract those 2 answers.

I’m really bad at explaining but I hope u get it

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Ive.

allochka39001 [22]

Answer:

50 + 200h

Step-by-step explanation:

4 0

3 years ago

不是我要的 营养分, 一、加; 的 第一 年11 在公司 16 115 更多 11 ( - 日) 上海

ludmilkaskok [199]

Answer:

您能再解釋一下嗎，謝謝

Step-by-step explanation:

3 0

3 years ago

Can someone help me please

masya89 [10]

Answer:

A) (3,-8); Reflection

Step-by-step explanation:

The question kind of gave you a hint. Look at how the coordinate point is arranged...

(-y,-x)

That means all positive become negatives and all negatives become positives. This gives you the coordinate of (3,-8).

As for reflection or rotation, the image's coordinates FLIPPED, like how images do in a mirror's reflection.

This means the answer would be A) (3,-8); Reflection.

4 0

3 years ago

Please people help me

Musya8 [376]

Answer:

x > 60

Step-by-step explanation:

From the picture attached,

An arrow starting with a hollow circle from x = 60, directing towards positive numbers (greater than 60).

So, hollow circle will represent an inequality with no sign of 'equal to' and arrow will represent the sign of greater than (As moving ahead of 60).

Inequality representing the picture will be,

x > 60

3 0

3 years ago

Find the inverse of the given matrix, if it exists.Aequals=left bracket Start 3 By 3 Matrix 1st Row 1st Column 1 2nd Column 0 3

BabaBlast [244]

Answer:

$A^{-1}=\left[ \begin{array}{ccc} \frac{1}{9} & \frac{4}{27} & - \frac{2}{27} \\\\ \frac{8}{9} & \frac{5}{27} & \frac{11}{27} \\\\ - \frac{4}{9} & \frac{2}{27} & - \frac{1}{27} \end{array} \right]$

Step-by-step explanation:

We want to find the inverse of $A=\left[ \begin{array}{ccc} 1 & 0 & -2 \\\\ 4 & 1 & 3 \\\\ -4 & 2 & 3 \end{array} \right]$

To find the inverse matrix, augment it with the identity matrix and perform row operations trying to make the identity matrix to the left. Then to the right will be inverse matrix.

So, augment the matrix with identity matrix:

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 4&1&3&0&1&0 \\\\ -4&2&3&0&0&1\end{array}\right]$

Subtract row 1 multiplied by 4 from row 2

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ -4&2&3&0&0&1\end{array}\right]$

Add row 1 multiplied by 4 to row 3

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&2&-5&4&0&1\end{array}\right]$

Subtract row 2 multiplied by 2 from row 3

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&0&-27&12&-2&1\end{array}\right]$

Divide row 3 by −27

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]$

Add row 3 multiplied by 2 to row 1

$\left[ \begin{array}{ccc|ccc}1&0&0&\frac{1}{9}&\frac{4}{27}&- \frac{2}{27} \\\\ 0&1&11&-4&1&0 \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]$

Subtract row 3 multiplied by 11 from row 2

$\left[ \begin{array}{ccc|ccc}1&0&0&\frac{1}{9}&\frac{4}{27}&- \frac{2}{27} \\\\ 0&1&0&\frac{8}{9}&\frac{5}{27}&\frac{11}{27} \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]$

As can be seen, we have obtained the identity matrix to the left. So, we are done.

6 0

3 years ago