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4 years ago

7

i’m having some trouble with these three questions it would be a big help if someone could help me out :)

1 answer:

algol [13]4 years ago

6 0

I’m not sure if I’m right but I think u have to add the 3 largest numbers in the population section and then add the other 3 least numbers in the same section and then u have to subtract those 2 answers.

I’m really bad at explaining but I hope u get it

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Find the primter of a traingle( the numbers around<br> it are 1/3 1/5 and 1/8) ASAP PLZ

mote1985 [20]

Answer:

79/120

Step-by-step explanation:

7 0

3 years ago

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In a school of 200 students, 90 students are in the marching band, 145 students are on sports teams and 75 students participate

mars1129 [50]

Answer:

c

Step-by-step explanation:

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3 years ago

Write the scientific notation in numerals. 6.4 x 107

bezimeni [28]

Hey!

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Writing scientific notation in numeral is solving for the equation.

Multiply 10 to 6.4 seven times.

6.4 x 10 = 64

64 x 10 = 640

640 x 10 = 6,400

6,400 x 10 = 64,000

64,000 x 10 = 640,000

640,000 x 10 = 6,400,000

6,400,000 x 10 = 64,000,000

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Hope This Helped! Good Luck!

3 0

4 years ago

What's the correct answer to this...?

Basile [38]

Answer:

-13

Step-by-step explanation:

f(-2) = 3(-2) - 7

f(-2) = -6 - 7

f(-2) = <u>-13</u>

8 0

4 years ago

Read 2 more answers

Can someone please help me with one or both of these problems, I'm so confused but the assignment is due soon!!

Firlakuza [10]

Answer:

First question: 1270

Second question: 4080

Step-by-step explanation:

Here is the Sum formula:

$S_{n}=\frac{n}{2}(a_{1}+a_{n})$

where n represents the number of terms, and

$a_{1}$ is the first term, and $a_{n}$ is the last term.

Let's look at the first question:

k is the first number of the sequence, 5, and 20 is the last number of the sequence.

You can find the first term ( $a_{1}$ ) by substituting k in the formula for 5.

3(5)+26=15+26=41

You can find the last term ( $a_{n}$ ) by substituting k for 20 into the formula.

3(20)+26=60+26=86

now, knowing there are 20 terms in total, $a_{1} =41$ , and $a_{n} =86$ , we can put it into the Sum formula.

$S_{20}= \frac{20}{2} (41+86)$

$S_{20}= \frac{20}{2} (127)$

$S_{20}= 10 (127)$

$S_{20}= 1270$

Answer to the first question: 1270

Next question:

Even though the given formula uses n as the variable, this problem works the same way as the previous one.

Substitute n in the formula for k, which is 5 to find the first term: 14(5)+29=99

Substitute 20 for n to find the second term: 14(20)+29=309

Now assemble the Sum formula:

$S_{20}= \frac{20}{2} (99+309)$

$S_{20}= \frac{20}{2} (408)$

$S_{20}= 10(408)$

$S_{20}=4080$

Answer to the second question: 4080

5 0

3 years ago