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3 years ago

Which intersection forms a parabola?

2 answers:

6 0

The answer is B. Parabola is a symmetrical open plane bend framed by the crossing point of a cone with a plane parallel to its side. The way of a shot affected by gravity in a perfect world takes after a bend of this shape.

lorasvet [3.4K]3 years ago

4 0

Answer:

A) A plane intersects only one nappe of a double-napped cone, and the plane is parallel to the generating line of the cone.

Step-by-step explanation:

A) Parabola

A plane intersects only one nappe of a double-napped cone, and the plane is parallel to the generating line of the cone.

The plane has to intersect with the base of the cone and forms a parabola.

B) Form Circle and hyperbola

C) Forms hyperbola

D) Forms circle

Hope this will helpful.

Thank you.

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A single die is rolled one time. Find the probability of rolling a number greater than 4 or less than 3.

Vika [28.1K]

Answer:

The probability of rolling a number greater than 4 or less than 3 is $\frac{2}{3}$

Solution:

In the given question there are two events as follows:

(a) Rolling a number greater than 4 i.e. A = {5,6}

(b) Rolling a number less than 3 i.e. B = {1,2}

Since a die has 6 numbers,

P(A) = $\frac{2}{6}$ where P(A) is the probability of occurrence of event A and P(B) = $\frac{2}{6}$

Since, Event A and Event B has nothing in common therefore they are mutually exclusive events.

P(A∪B) = P(A) + P(B)

$=\frac{2}{6}+\frac{2}{6}$

$=\frac{4}{6}$

$=\frac{2}{3}$

Therefore the probability of getting a number greater than 4 or less than 3 is $\frac{2}{3}$

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3 years ago

If f(x) = log2 (x + 1), what is f-1(2)? (2 points)

Soloha48 [4]

as you already know, to get the inverse of any expression, we start off by doing a quick switcheroo on the variables, and then solve for "y".

$\bf \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad \stackrel{\textit{we'll use this one}}{a^{log_a x}=x} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{f(x)}{y}=\log_2(x+1)\implies \stackrel{\textit{quick switcheroo}}{\underline{x}=\log_2(\underline{y}+1)}\implies 2^x=2^{\log_2({y}+1)} \\\\\\ 2^x=y+1\implies 2^x-1=\stackrel{f^{-1}(x)}{y} \\\\[-0.35em] ~\dotfill\\\\ 2^2-1=f^{-1}(2)\implies 3=f^{-1}(2)$

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Answer:

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2 years ago

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Rus_ich [418]

Answer:

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Step-by-step explanation:

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